Q.Let us assume that the demand curve is described by the line q=mp+b. Find its equation given that a promoter discovers that the demand for theatre tickets is 1200 when the price is Rs. 400, but decreases to 900 when the price is raised to Rs. 450.
Concept understanding — Various Forms of the Equation of a Line
Various Forms of the Equation of a Line
Imagine you want to describe a straight line to someone who has never seen it. You could say "it goes through this point and slants like this" — that's the intuition. In coordinate geometry, we capture that same idea using equations. A line is just the set of all points (x,y) that satisfy a certain condition. Different conditions give us different forms of the same line.
1. Slope-Intercept Form: y=mx+c
This is the most familiar form. Here m is the slope (steepness) and c is the y-intercept (where the line cuts the y-axis).
Why it works: If you know how much the line rises for every unit it runs horizontally (m), and where it starts on the y-axis (c), you can write the equation directly.
To find m: pick any two points (x1,y1) and (x2,y2) on the line, then m=x2−x1y2−y1.
Example: A line with slope 2 and y-intercept -3 is y=2x−3.
2. Point-Slope Form: y−y1=m(x−x1)
Suppose you know the slope m and one point (x1,y1) on the line. The point-slope form says: the difference in y from that point equals the slope times the difference in x.
Intuition: If you stand at (x1,y1) and move horizontally by (x−x1), you must move vertically by m times that amount to stay on the line.
y−y1=m(x−x1)
Example: Line through (2,5) with slope −4: y−5=−4(x−2).
3. Two-Point Form: y2−y1y−y1=x2−x1x−x1
If you know two points (x1,y1) and (x2,y2), you don't need to compute slope separately. This form says the ratio of vertical change to total vertical span equals the ratio of horizontal change to total horizontal span.
Why it's natural: It's just the condition that the three points (x1,y1), (x2,y2), and (x,y) are collinear — they all lie on the same straight line.
If x1=x2 or y1=y2, the denominator becomes zero. That's fine — it just means the line is vertical or horizontal. Use the appropriate special form instead.
Example: Line through (1,2) and (3,8): 8−2y−2=3−1x−1, which simplifies to y=3x−1.
4. Intercept Form: ax+by=1
Here a is the x-intercept (where the line cuts the x-axis) and b is the y-intercept.
Intuition: When y=0, the equation gives x=a; when x=0, it gives y=b. So the line passes through (a,0) and (0,b).
This form only works if the line cuts both axes (i.e., a=0 and b=0). A line through the origin cannot be written this way.
Example: A line with x-intercept 4 and y-intercept -3: 4x+−3y=1, or 4x−3y=1.
5. Normal Form: xcosθ+ysinθ=p
This is the most geometric form. Here p is the perpendicular distance from the origin to the line, and θ is the angle that this perpendicular makes with the positive x-axis.
Why it's useful: It directly gives the distance of the line from the origin — something the other forms hide.
| Form | When to use |
|------|-------------|
| Slope-intercept | Slope and y-intercept known |
| Point-slope | Slope and one point known |
| Two-point | Two points known |
| Intercept | Both intercepts known |
| Normal | Distance from origin and direction of perpendicular known |
6. General (Standard) Form: Ax+By+C=0
Every line can be written this way, with A and B not both zero. This is the universal form — it handles vertical lines (B=0), horizontal lines (A=0), and everything in between.
Converting between forms: You can always rearrange any of the above into Ax+By+C=0, and vice versa.
To find the slope from the general form: m=−BA (provided B=0).
Putting It All Together
All these forms describe the same geometric object — a straight line — just from different starting information. The skill is to pick the form that matches what you're given, then convert if needed.
Example: A line passes through (2,3) and (5,7). Write its equation in all forms.
- Two-point: 7−3y−3=5−2x−2⟹4y−3=3x−2
- Slope: m=34, so point-slope: y−3=34(x−2)
- Slope-intercept: y=34x+31
- General: 4x−3y+1=0
- Intercept: −1/4x+1/3y=1 (here a=−41, b=31)
- Normal: p=42+(−3)2∣1∣=51, cosθ=54, sinθ=−53, so x(54)+y(−53)=51
Each form reveals something different about the same line.
Since the demand curve is a straight line q=mp+b, the two given (price, demand) pairs determine its slope and intercept.
q=−6p+3600
Two given (price, demand) points determine the slope m and intercept b of the straight-line demand equation q=mp+b.
Straight line through two points (p1,q1) and (p2,q2):
m=p2−p1q2−q1,q−q1=m(p−p1)
- Identify the given data as two points (p,q).
(p1,q1)=(400,1200),(p2,q2)=(450,900)
- Compute the slope m.
m=p2−p1q2−q1=450−400900−1200=50−300=−6
- Find b using point (400,1200) in q=mp+b.
1200=(−6)(400)+b=−2400+b
b=1200+2400=3600
- Write the demand equation.
q=−6p+3600
- Self-check. At p=400: q=−6(400)+3600=−2400+3600=1200 ✓. At p=450: q=−6(450)+3600=−2700+3600=900 ✓. Both given points satisfy the equation. The negative slope also makes economic sense: demand falls as price rises.
q=−6p+3600 (demand for tickets falls by 6 for every ₹1 rise in price).
- CBSE 2025Set ANNUAL1 markMCQQ.Intercept form of a straight line is(a) ax+by=1(b) ax−by=1(c) ax+by=−1(d) None of these
›Reveal solutionSolution
The intercept form of a line with x-intercept a and y-intercept b is ax+by=1.
A line that cuts the x-axis at (a,0) and the y-axis at (0,b) has the equation:
ax+by=1
This can be verified: at (a,0), aa+b0=1 holds; at (0,b), a0+bb=1 holds.
✓Final answer(a) ax+by=1
- CBSE 2024Set ANNUAL1 markMCQQ.Find the equation of the straight line which passes through the point (3,4) and whose x-intercept is equal to y-intercept.(a) x+y=7(b) x+y=3(c) x−y=2(d) None of these
›Reveal solutionSolution
A line with equal x- and y-intercepts (both =a) has the form x+y=a; substitute the given point to find a.
If a line has x-intercept =y-intercept =a, its intercept form ax+ay=1 simplifies to:
x+y=a
Since the line passes through (3,4), substitute:
3+4=a⟹a=7
So the equation of the line is:
x+y=7
(The alternative case a=0, a line through the origin with slope −1, i.e. y=−x, does not pass through (3,4) since 3=−4, so it's not a valid alternative here.)
✓Final answer(a) x+y=7.
- CBSE 2022Set ANNUAL1 markQ.The equation of line passing through (1, 2) and slope 3 is ............ .
›Reveal solutionSolution
Using point-slope form with point (1,2) and slope 3 gives 3x−y−1=0.
Point-slope form of a line through (x1,y1) with slope m:
y−y1=m(x−x1)
With (x1,y1)=(1,2) and m=3:
y−2=3(x−1)
y−2=3x−3
3x−y−1=0
✓Final answerThe equation of the line is 3x−y−1=0 (equivalently, y=3x−1).
- CBSE 2021Set ANNUAL1 markMCQQ.The equation of line passing through (2, 3) and making an angle 45° with positive x-axis is:(a) x − y + 1 = 0(b) x + y − 5 = 0(c) x + y − 1 = 0(d) None of these
›Reveal solutionSolution
Slope =tan45°=1; point-slope form through (2,3) reduces to x−y+1=0.
Slope of a line making angle 45° with the positive x-axis: m=tan45°=1.
Point-slope form through (2,3):
y−3=1⋅(x−2)
y=x+1
x−y+1=0
✓Final answerx−y+1=0 — option (a).
- CBSE 2020Set ANNUAL1 markMCQQ.Find the equation of the straight line which passes through the point (2,3) and cut off equal intercepts on the axes.(a) x+y=4(b) x+y=5(c) x+y=6(d) 2x+3y=9
›Reveal solutionSolution
A line with equal intercepts a on both axes has the equation x+y=a; substitute the given point to find a.
Intercept form of a line with equal intercepts a on the x- and y-axes: ax+ay=1, i.e. x+y=a.
This line passes through (2,3): 2+3=a⇒a=5
So the line is x+y=5.
✓Final answer(b) x+y=5
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