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Worked Examples · Example 3

Q.The average of 4 positive integers is 39. The highest integer is 73 and the lowest integer is 19. The difference between the remaining two integers in 18. Find the remaining integers.

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Find the total sum from the average, subtract the known highest and lowest, then solve a sum-and-difference pair of equations for the remaining two integers.

Average =SumNumber of terms= \dfrac{\text{Sum}}{\text{Number of terms}}; for two numbers with sum SS and difference DD (x>yx>y): x=S+D2x = \dfrac{S+D}{2}, y=S−D2y = \dfrac{S-D}{2}.

  1. Sum of the 4 positive integers == Average ×\times Count =39×4=156= 39 \times 4 = 156.
  2. Sum of the remaining two integers =156−73−19=64= 156 - 73 - 19 = 64. …

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