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Exercise 5.1 · Q15

Q.Insert five numbers between 8 and 26 such that the resulting sequence is an A.P.

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Inserting 5 numbers between 8 and 26 makes a 7-term A.P. with common difference 33; the inserted numbers are 11,14,17,20,2311,14,17,20,23.

If kk numbers are inserted between aa and bb to form an A.P. of k+2k+2 terms, then b=a+(k+1)d⇒d=b−ak+1b=a+(k+1)d\Rightarrow d=\dfrac{b-a}{k+1}.

  1. Here a=8a=8, b=26b=26, k=5k=5 numbers to insert, so the total number of terms is k+2=7k+2=7.
  2. d=b−ak+1=26−86=186=3d=\dfrac{b-a}{k+1}=\dfrac{26-8}{6}=\dfrac{18}{6}=3. …

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