Q.Write a program to read a list of n integers and find their median. Note: The median value of a list of values is the middle one when they are arranged in order. If there are two middle values then take their average. Hint: You can use an built-in function to sort the list

Sort first; then the median is the middle element (odd n) or the average of the two middles (even n).

n = int(input("How many numbers? "))
numbers = [int(input("Enter number: ")) for i in range(n)]
numbers.sort()
mid = n // 2
if n % 2 == 1:
    median = numbers[mid]
else:
    median = (numbers[mid - 1] + numbers[mid]) / 2
print("Median =", median)

• n = 5, inputs 21, 3, 45, 8, 19 → sorted [3, 8, 19, 21, 45] → middle index 2 → 19 …

The idea. The median is defined on ordered values, so sorting is the essential first step — exactly what the hint points at (sort()/sorted()). After sorting, integer arithmetic on indices does the rest: with 0-based indexing, the middle of an odd-length list is index n//2, and an even-length list has its two middles at n//2 - 1 and n//2.

Program:

n = int(input("How many numbers? "))
numbers = []
for i in range(n):
    numbers.append(int(input("Enter number " + str(i + 1) + ": ")))

numbers.sort()                      # built-in sort, ascending
mid = n // 2

if n % 2 == 1:                      # odd count -> single middle value
    median = numbers[mid]
else:                               # even count -> average the two middles
    median = (numbers[mid - 1] + numbers[mid]) / 2

print("Sorted list:", numbers)
print("Median =", median)

Expected output — odd case (n = 5, inputs 21, 3, 45, 8, 19):

Sorted list: [3, 8, 19, 21, 45]
Median = 19

Expected output — even case (n = 4, inputs 10, 40, 20, 30):

Sorted list: [10, 20, 30, 40]
Median = 25.0

Index working: