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Problems · Example 9.13

Q.Write structures of different isomers corresponding to the 5 th member of alkyne series. Also write IUPAC names of all the isomers. What type of isomerism is exhibited by different pairs of isomers?

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The 5th alkyne is CX6HX10\ce{C6H10} (hexyne). It has seven alkyne isomers — hex-1-yne, hex-2-yne, hex-3-yne, 3-methylpent-1-yne, 4-methylpent-1-yne, 4-methylpent-2-yne and 3,3-dimethylbut-1-yne — showing position isomerism (same skeleton, different triple-bond position) and chain isomerism (different skeletons).

Identifying the 5th member

The alkyne homologous series (CXnHX2n−2\ce{C_nH_{2n-2}}) runs ethyne (CX2HX2\ce{C2H2}), propyne (CX3HX4\ce{C3H4}), butyne (CX4HX6\ce{C4H6}), pentyne (CX5HX8\ce{C5H8}) — so the 5th member is CX6HX10\ce{C6H10}, hexyne.

Generating every alkyne isomer systematically

Six-carbon straight chain. The triple bond can sit at three distinct positions:

  1. Hex-1-yne — HC≡C−CHX2−CHX2−CHX2−CHX3\ce{HC#C-CH2-CH2-CH2-CH3}
  2. Hex-2-yne — CHX3−C≡C−CHX2−CHX2−CHX3\ce{CH3-C#C-CH2-CH2-CH3}
  3. Hex-3-yne — CHX3−CHX2−C≡C−CHX2−CHX3\ce{CH3-CH2-C#C-CH2-CH3} (numbering from either end gives 3 — the symmetric case)

Five-carbon chain with one methyl branch. A triple-bonded carbon can hold only one substituent, so the methyl must sit on a saturated carbon:

4. 3-Methylpent-1-yne — HC≡C−CH(CHX3)−CHX2−CHX3\ce{HC#C-CH(CH3)-CH2-CH3}

5. 4-Methylpent-1-yne — HC≡C−CHX2−CH(CHX3)−CHX3\ce{HC#C-CH2-CH(CH3)-CH3}

6. 4-Methylpent-2-yne — CHX3−C≡C−CH(CHX3)−CHX3\ce{CH3-C#C-CH(CH3)-CH3}

Four-carbon chain with two methyl branches. Both methyls must go on the one available saturated interior carbon:

7. 3,3-Dimethylbut-1-yne — HC≡C−C(CHX3)X2−CHX3\ce{HC#C-C(CH3)2-CH3}

No further skeleton works: a triple bond cannot be accommodated on a more highly branched four-carbon frame without exceeding carbon's four bonds.

The isomerism shown by different pairs …

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