The IUPAC name for the compound shown (a benzene ring bearing –Cl at C-1, –NO2 on the carbon adjacent to –Cl,

NCERT Exemplar · Q3

Q. The IUPAC name for the compound shown (a benzene ring bearing -Cl at C-1, -NO2 on the carbon adjacent to -Cl, and -CH3 para to -Cl) is ______.

(i) 1-Chloro-2-nitro-4-methylbenzene

(ii) 1-Chloro-4-methyl-2-nitrobenzene

(iii) 2-Chloro-1-nitro-5-methylbenzene

(iv) m-Nitro-p-chlorotoluene

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Concept understanding — IUPAC Nomenclature

IUPAC Nomenclature (Organic Compounds)

IUPAC nomenclature is a systematic way to name a compound so that its name alone tells you its exact structure, with no ambiguity. Every organic name follows the same underlying recipe, whatever the functional group.

The Recipe

Identify the principal characteristic group. If the molecule has a functional group senior enough to be named as a suffix (carboxylic acid > ester > amide > nitrile > aldehyde > ketone > alcohol > amine, and so on down the seniority order), that group decides the suffix and must be included in the parent chain. A halogen is never senior enough to be a suffix — it is always named as a prefix ("halo-"), whatever else is present.
Choose the parent chain. The parent is the longest continuous carbon chain that contains the principal characteristic group (if there is one). Among chains of the same length, the one with the most substituents wins.
Number the chain. Number from whichever end gives the LOWEST LOCANT to the principal characteristic group first. If there is no principal group (e.g. a simple haloalkane, or an alkene with a halogen substituent), lowest locant goes to the site of unsaturation (double/triple bond) first, then to substituents as a set.

Watch out

When two numbering directions give the SAME locant for the principal group/unsaturation (a genuine tie), the tie-break is the lowest locant SET for the substituents as a group — compare the two sets at their first point of difference. Only if the sets are themselves tied does the alphabetically-first substituent get the lower number.
Name and cite the substituents as prefixes, in alphabetical order (ignoring multiplying prefixes like di-/tri- but not ignoring structural prefixes like iso-/cyclo-), each with its own locant.
Assemble the name: locants + substituent prefixes (alphabetical) + parent chain name + suffix (if any).

Worked Example

$CH_3-CH(Cl)-CH(CH_3)-CH_2-CH_3$ : the longest chain is 5 carbons (pentane), no principal characteristic group (just a halogen substituent), so number for the lowest locant set. From the left: Cl at C2, methyl at C3 → set {2,3}. From the right: methyl at C3, Cl at C4 → set {3,4}. {2,3} is lower, so numbering from the left wins: 2-chloro-3-methylpentane.

Tip

A locant TIE (both directions give the same first-point-of-difference number) is common on short/symmetric chains — always check both directions explicitly rather than assuming "number from the end nearer the first substituent mentioned in the name" is automatically correct.

Common Mistakes

Picking a chain that is NOT the longest one just because it "looks simpler" — always verify no longer chain exists, including chains that run through what looks like a branch.
Forgetting the alphabetical-order rule for citing substituents (locants are chosen by the lowest-locant rule; the ORDER they're written in the name is alphabetical, not by locant).
Treating a halogen as if it could ever be the principal characteristic group / suffix — it cannot; it is always a prefix, however many are present.

IUPAC nomenclature is a foundational skill taught in the NCERT/CBSE Class 11 Chemistry chapter on Organic Chemistry: Some Basic Principles and Techniques, and ‘IUPAC nomenclature rules and examples’ is one of the most searched important-question topics for board exams, JEE Main and NEET. Naming organic compounds correctly underpins almost every other organic-chemistry question asked in competitive exams.

Why this formula?

IUPAC Nomenclature: Why the Rules Work the Way They Do

IUPAC nomenclature is not a single formula, but a system of rules designed to give every organic compound a unique, unambiguous name. The "why" behind these rules lies in clarity, consistency, and communication — ensuring that a chemist in Tokyo and one in Toronto draw the same structure from the same name.

1. The Core Principle: The Longest Carbon Chain

Rule: Identify the longest continuous chain of carbon atoms. This becomes the parent chain (e.g., pentane, hexane).

Why?

The longest chain represents the backbone of the molecule.
It gives the most stable, fundamental name — shorter chains would be branches, not the main structure.
Example: In a molecule with 5 carbons in a row and a 2-carbon branch, calling it "pentane" (not "ethane") tells you the core skeleton is 5 carbons long.

Key idea: The parent chain is the maximum continuous path — not necessarily the one that looks "straight" on paper.

2. Numbering: Lowest Locants (The "First Point of Difference" Rule)

Rule: Number the parent chain so that substituents get the smallest possible numbers. When there's a tie, compare the first point of difference.

Why?

This ensures reproducibility — two chemists will always number the same way.
It avoids ambiguity: "2-methylpentane" is unambiguous; "3-methylpentane" would be a different compound.
The first point of difference rule: If you have substituents at positions 2,4 and 3,5, choose 2,4 because 2 < 3 (the first number is smaller).

Example:

For a methyl group on carbon 2 vs. carbon 4 of a 5-carbon chain:
- 2-methylpentane (correct)
- 4-methylpentane (wrong — higher number)

3. Alphabetical Order of Substituents

Rule: List substituents in alphabetical order (ignoring prefixes like di-, tri-, sec-, tert- but not iso-).

Why?

Alphabetical order is a universal sorting convention — no need to remember priority based on size or complexity.
It makes names searchable and predictable.
Example: "3-ethyl-2-methylpentane" (e before m) — not "2-methyl-3-ethylpentane".

Exception: Prefixes like iso- and neo- are considered part of the name (e.g., isopropyl comes before methyl because "i" < "m").

4. Multiple Bonds: The "Lowest Locant" Rule for Alkenes/Alkynes

Rule: Number the chain so that the double or triple bond gets the lowest possible number, even if it means giving a substituent a higher number.

Why?

The functional group (alkene/alkyne) is more important than alkyl substituents.
The bond position defines the compound's reactivity and geometry.
Example: In pent-2-ene (not pent-3-ene), the double bond is between carbons 2 and 3 — the lower number (2) is used.

Priority order:

Principal functional group (e.g., -OH, -COOH, C=C)
Multiple bonds
Substituents (alkyl, halo, etc.)

5. The "Suffix" and "Prefix" System

Rule: The principal functional group determines the suffix (e.g., -ol for alcohol, -al for aldehyde). Other groups become prefixes (e.g., chloro-, hydroxy-).

Why?

The suffix tells you the most important chemical feature at a glance.
Prefixes are secondary — they modify the parent name without changing its core identity.
Example: "3-chloropropan-1-ol" — the "-ol" tells you it's an alcohol; "chloro-" is just a substituent.

6. Why "E/Z" and "R/S" Exist

Rule: Use E/Z for alkene geometry (based on Cahn-Ingold-Prelog priority) and R/S for chiral centers.

Why?

Simple cis/trans fails when there are more than two different substituents.
E/Z and R/S are unambiguous — they assign priority based on atomic number, not just "same side" or "opposite side".
This prevents confusion: (E)-3-methylpent-2-ene is a specific isomer; "cis" would be ambiguous here.

Summary: The "Why" in One Table

Rule	Purpose
Longest chain	Defines the core skeleton
Lowest locants	Ensures unique numbering
Alphabetical order	Universal sorting
Functional group priority	Highlights reactivity
E/Z, R/S	Handles stereochemistry

Final thought: IUPAC nomenclature is a language, not a formula. Every rule exists to eliminate ambiguity — so that a name is a perfect blueprint for a molecule.

Number the ring so the alphabetically-first substituent (chloro) is C-1 and the locant set is lowest: Cl at 1, NO $_2$ at 2, CH $_3$ at 4. Citing the substituents alphabetically gives 1-chloro-4-methyl-2-nitrobenzene — option (ii).

For a polysubstituted benzene, IUPAC nomenclature rests on two rules: cite the substituents alphabetically in the name, and number the ring to give the lowest set of locants.

Assign the locants. The ring carries chloro, methyl, and nitro. Fix the geometry from the description: chloro on one carbon, nitro on the carbon adjacent to it, methyl para to the chloro. Placing chloro at C-1, the nitro (adjacent) is at C-2 and the methyl (para) is at C-4:

\text{Cl at C-1}, \quad \text{NO}_2 \text{ at C-2}, \quad \text{CH}_3 \text{ at C-4}

The locant set is $\{1, 2, 4\}$ . Numbering in the opposite direction would put the nitro at C-6, giving $\{1, 4, 6\}$ , which is higher — so $\{1, 2, 4\}$ is correct.

Write the name. List the substituents in alphabetical order (chloro, methyl, nitro), each with its locant, and append the parent "benzene": 1-chloro-4-methyl-2-nitrobenzene.

Watch out

Do not order the substituents by their position numbers (that would give "1-chloro-2-nitro-4-methyl"). IUPAC orders substituents alphabetically by name, independent of their locants.

Checking the options:

(i) 1-Chloro-2-nitro-4-methylbenzene — correct locants but the substituents are not in alphabetical order.
(ii) 1-Chloro-4-methyl-2-nitrobenzene — correct locants and alphabetical order. ✓
(iii) 2-Chloro-1-nitro-5-methylbenzene — numbers from the wrong atom; chloro (alphabetically first) should take the lowest locant.
(iv) m-Nitro-p-chlorotoluene — uses common/relative names, not a systematic IUPAC name.

✓Final answer

The correct IUPAC name is 1-chloro-4-methyl-2-nitrobenzene, option (ii) .

Same / Similar Concept — real previous-year questions on the same or a closely similar concept, not this exact question.

Showing the 12 most recent of 96 on this concept.

CBSE 2026Set A1 markMCQ
$Q. The IUPAC name of CH3CH2COCH2CH3 is$
(a) Diethyl ketone
(b) 3-Pentanone
(c) 2-Pentanone
(d) Methyl propyl ketone
›Reveal solutionSolution

Number the five-carbon chain to give the C=O the lowest locant: the ketone carbon is C-3, so the IUPAC name is pentan-3-one (3-pentanone).

Structure: CH3-CH2-CO-CH2-CH3. The longest chain containing the carbonyl has 5 carbons -> pentanone. Numbering from either end places the carbonyl carbon at position 3. Hence the IUPAC name is pentan-3-one (3-pentanone). (Diethyl ketone is the common/trivial name, not the IUPAC name.)

✓Final answer
$(b) 3-Pentanone (pentan-3-one).$
CBSE 2026Set ANNUAL1 markMCQ
$Q. IUPAC name of [a benzene ring with an -OC2H5 (ethoxy) group attached] is$
(a) Benzyl ethoxide
(b) Benzene ethoxide
(c) Ethoxybenzene
(d) Ethoxybenzoyl
›Reveal solutionSolution

Simple ethers with one aromatic and one alkyl group are IUPAC-named as 'alkoxy' + 'benzene', treating the -OR group as a substituent on the ring.

The compound is a benzene ring bearing an ethoxy substituent (-O-C2H5). Following IUPAC substitutive nomenclature for ethers, the smaller/simpler group's oxygen chain is named as an 'alkoxy' prefix attached to the parent (here benzene):

-OC2H5 = ethoxy group

So the compound is Ethoxybenzene (common name: phenetole).

'Benzyl ethoxide' and 'Benzene ethoxide' are not valid IUPAC names (benzyl would mean a -CH2-C6H5 group, not directly relevant here, and 'ethoxide' misnames the functional class), and 'Ethoxybenzoyl' incorrectly implies an acyl (-COR) group, which is absent.

✓Final answer
$(c) Ethoxybenzene.$
CBSE 2026Set ANNUAL1 markMCQ
$Q. IUPAC name of CH3COOH is:$
(a) Ethanol
(b) ethanoic acid
(c) Ethanal
(d) ethane
›Reveal solutionSolution

CH₃COOH is acetic acid, IUPAC name ethanoic acid.

CH₃COOH is a two-carbon carboxylic acid, commonly called acetic acid. In IUPAC nomenclature, carboxylic acids are named by replacing the "-e" of the corresponding alkane name with "-oic acid". The two-carbon alkane is ethane, so CH₃COOH becomes ethanoic acid.

✓Final answer
$(b) ethanoic acid.$
CBSE 2026Set ANNUAL1 markMCQ
$Q. The IUPAC name of Formic acid is :$
(a) Methanoic acid
(b) Ethanoic acid
(c) Ethandioic acid
(d) Methandioic acid
›Reveal solutionSolution
Formic acid, HCOOH, is the one-carbon carboxylic acid, named methanoic acid by IUPAC rules.

Formic acid has the structure H–COOH (a single carbon bearing the carboxyl group). To name a carboxylic acid by IUPAC nomenclature:

Select the longest carbon chain including the –COOH carbon.

Replace the terminal '-e' of the corresponding alkane name with '-oic acid'.

Here the chain has just one carbon (methane), so the name becomes methanoic acid.

Ethanoic acid (option b) is acetic acid, CH₃COOH (two carbons).

Ethandioic acid / methandioic acid (options c, d) refer to oxalic acid, HOOC–COOH (a dicarboxylic acid), not formic acid.

✓Final answer
$(a) Methanoic acid.$
CBSE 2026Set ANNUAL1 markMCQ
$Q. The IUPAC name of isobutyl chloride is$
(a) 2-chlorobutane
(b) 1-chloro-2-methyl propane
(c) 2-chloro-2-methyl propane
(d) 1-chlorobutane
›Reveal solutionSolution

Isobutyl chloride has the structure (CH3)2CH-CH2-Cl. Number the longest chain (propane, 3 carbons) so the substituent (Cl) gets the lowest locant, then name the methyl branch.

Structure of isobutyl chloride: (CH3)2CH-CH2-Cl

This can be redrawn as: Cl-CH2-CH(CH3)-CH3

Step 1: Identify the longest carbon chain containing the point of attachment of Cl. That's a 3-carbon (propane) chain: C1(CH2Cl)-C2(CH, bearing a methyl branch)-C3(CH3).

Step 2: Number the chain to give Cl the lowest possible locant. Numbering from the Cl end: C1 = CH2Cl, C2 = CH(CH3), C3 = CH3.

Step 3: Cl is on C1 (chloro at position 1); the methyl branch is on C2 (2-methyl).

Step 4: Assemble the IUPAC name: 1-chloro-2-methylpropane.

✓Final answer
$(b) 1-chloro-2-methyl propane.$
CBSE 2026Set ANNUAL1 mark
$Q. Write IUPAC name of the following compound:$
›Reveal solutionSolution
Numbering the 6-carbon chain from the -COOH carbon (C1) puts the ketone at C4 and the terminal bromine at C6, giving 6-bromo-4-oxohexanoic acid.

The drawn structure is a straight 6-carbon chain: BrCH2-CH2-CO-CH2-CH2-COOH, i.e. a terminal -CH2Br at one end and -COOH at the other, with a ketone in between.

The carboxylic acid (-COOH) is the senior group and is numbered C1.

Numbering from that end: C1 (COOH), C2 (CH2), C3 (CH2), C4 (the ketone C=O), C5 (CH2), C6 (the terminal CH2Br).

Parent chain = 6 carbons = hexanoic acid; the ketone is cited as the prefix 'oxo' at C4, and 'bromo' at C6 (bromo before oxo alphabetically).

Name: 6-bromo-4-oxohexanoic acid.

✓Final answer
$6-Bromo-4-oxohexanoic acid, i.e. HOOC-CH2-CH2-CO-CH2-CH2Br.$
CBSE 2026Set ANNUAL1 markMCQ
$Q. The IUPAC name of CH3COOH is$
(a) Acetic acid
(b) Formic acid
(c) Ethanoic acid
(d) Methanoic acid
›Reveal solutionSolution

CH3COOH = ethanoic acid (IUPAC).

CH3COOH has two carbon atoms and a −COOH group. In IUPAC nomenclature, a two-carbon carboxylic acid is 'ethan' (two carbons) + 'oic acid' = ethanoic acid. Its common (trivial) name is acetic acid. Formic acid / methanoic acid is HCOOH.

✓Final answer
$(C) Ethanoic acid.$
CBSE 2026Set ANNUAL1 markMCQ
$Q. The IUPAC name of CH3-CH(OH)-CH3 is$
(a) Propan-1-ol
(b) Propan-2-ol
(c) n-propyl alcohol
(d) Isopropyl alcohol
›Reveal solutionSolution

CH3−CH(OH)−CH3 = propan-2-ol.

The chain has three carbons (propane). The −OH group is attached to the central (second) carbon. Numbering to give the OH the lowest locant places it at position 2, so the IUPAC name is propan-2-ol (common name isopropyl alcohol).

✓Final answer
$(B) Propan-2-ol.$
CBSE 2026Set ANNUAL1 markMCQ
$Q. The structure of a valuable organic compound used as solvent in many chemical industries is shown below (a central carbon bearing a CH₃ group above, a CH₃ group to the left, an OH group below, and a -CH₂-OCH₃ group to the right). The IUPAC name of the organic compound is$
(a) 1-methoxy-2-methylpropan-2-ol
(b) 3-methoxy-2-methylpropan-2-ol
(c) 1-methoxy-3-methylpropan-3-ol
(d) 2-methoxy-2-methylpropan-2-ol
›Reveal solutionSolution
The structure is (CH₃)₂C(OH)CH₂OCH₃; the parent is propan-2-ol with a 2-methyl and a 1-methoxy substituent, giving 1-methoxy-2-methylpropan-2-ol — option (A).

The central carbon bears two $CH_3$ groups, an $OH$ , and a $-CH_2-OCH_3$ group, so the molecule is

$(CH_3)_2C(OH)-CH_2-OCH_3.$

Naming:

The longest carbon chain containing the –OH is three carbons (propane): $C1 = CH_2(OCH_3)$ , $C2 = C(OH)(CH_3)$ , $C3 = CH_3$ .

The principal characteristic group is $-OH$ , so it becomes the suffix -ol and gets the lowest locant. $OH$ is on $C2$ → propan-2-ol.

Substituents: a methyl group on $C2$ (the second $CH_3$ ) and a methoxy ( $-OCH_3$ ) group on $C1$ .

Arranged alphabetically (methoxy before methyl): 1-methoxy-2-methylpropan-2-ol.

✓Final answer
$(A) 1-methoxy-2-methylpropan-2-ol.$
CBSE 2025Set 56/5/11 markMCQ
$CH_3 - CH_2 - N(CH_3) - CH_2 - CH_2 - CH_3$
›Reveal solutionSolution
The compound is a secondary amine with an ethyl and a methyl group on the nitrogen, and a three-carbon chain as the parent. The correct IUPAC name is N-ethyl-N-methylpropan-1-amine, which corresponds to option (B).

The key to naming amines under IUPAC rules is to identify the longest continuous carbon chain attached to the nitrogen — that becomes the parent alkane name, with the suffix "-amine". The other groups on the nitrogen are treated as substituents, prefixed with "N-" to show they are attached to the nitrogen atom, not to the carbon chain.

Let's break this down step by step.

Draw the structure from the given condensed formula.

The formula is $CH_3 - CH_2 - N(CH_3) - CH_2 - CH_2 - CH_3$ .

The nitrogen has three bonds: one to an ethyl group ( $-CH_2CH_3$ ), one to a methyl group ( $-CH_3$ ), and one to a propyl group ( $-CH_2CH_2CH_3$ ). So the molecule is:

CH3 | CH3-CH2-N-CH2-CH2-CH3

The nitrogen is connected to three different alkyl groups: ethyl, methyl, and propyl.

Identify the parent chain.

The IUPAC rule for amines: the parent chain is the longest continuous carbon chain attached directly to the nitrogen. Here, the chain on the right is $CH_2-CH_2-CH_3$ — that's three carbons, a propyl group. The chain on the left is $CH_2-CH_3$ — two carbons, an ethyl group. The methyl group ( $CH_3$ ) is just one carbon.

So the longest chain is the three-carbon chain (propyl). The parent name becomes propan-1-amine (since the nitrogen is at the end of the chain, carbon 1).

Name the substituents on the nitrogen.

The other two groups attached to the nitrogen are an ethyl group ( $-CH_2CH_3$ ) and a methyl group ( $-CH_3$ ). Since they are on the nitrogen, not on the carbon chain, they are prefixed with "N-".

Alphabetically, ethyl comes before methyl. So we write N-ethyl-N-methyl.

Combine the parts.

The full name is: N-ethyl-N-methylpropan-1-amine.

Tip

A common shortcut: if the nitrogen has two small alkyl groups and one longer chain, the longest chain is always the parent. The "N-" prefixes tell the reader exactly where those groups are — without them, the name would imply the groups are on the carbon chain, which would be a different compound.

Watch out

A frequent mistake is to pick the wrong parent chain. Some students might see the ethyl group on the left and think the parent is pentane (five carbons), but that would ignore the rule that the longest chain attached to nitrogen is the parent. Here, the propyl chain is the longest, so the parent is propan-1-amine, not pentan-2-amine. Option (A) is wrong for exactly this reason.

Now check the options:

(A) N-methylpentan-2-amine — this would imply a five-carbon parent chain with the nitrogen on carbon 2, which is not the longest chain attached to N.

(B) N-ethyl-N-methylpropan-1-amine — matches our name exactly.

(C) N,N-diethylpropan-1-amine — would require two ethyl groups on N, but we have one ethyl and one methyl.

(D) N,N-dimethylpropan-1-amine — would require two methyl groups on N, but we have one methyl and one ethyl.

✓Final answer
$The correct IUPAC name is N-ethyl-N-methylpropan-1-amine, which is option (B) .$
CBSE 2025Set X11 markMCQ
$\text{H}_3\text{C}-\underset{\underset{\text{Br}}{|}}{\text{CH}}-\text{CH}_2-\underset{\overset{\text{O}}{||}}{\text{C}}-\text{H}$
(a) 3–bromobutyraldehyde
(b) 2–bromopropanaldehyde
(c) 3–bromobutanal
(d) 2–bromobutanal
›Reveal solutionSolution
The compound is $\text{CH}_3\text{-CH(Br)-CH}_2\text{-CHO}$ , a 4-carbon aldehyde with bromine on C-3 → 3-bromobutanal.

The structure is $\text{H}_3\text{C-CH(Br)-CH}_2\text{-CHO}$ .

The principal functional group is the aldehyde (–CHO), so it gets the lowest locant. Numbering starts at the carbonyl carbon: C1 = CHO, C2 = $\text{CH}_2$ , C3 = CH(Br), C4 = $\text{CH}_3$ .

Longest chain = 4 carbons → butanal.

Bromine substituent is on C-3 → 3-bromo.

Hence the IUPAC name is 3-bromobutanal. (Options with "butyraldehyde"/"propanaldehyde" use non-IUPAC or wrong chain length.)

✓Final answer
$(c) 3-bromobutanal$
CBSE 2025Set D1 markMCQ
$Q. The IUPAC name of CH3COOC2H5 is$
(a) Methyl propanoate
(b) Ethyl ethanoate
(c) Acetoethane
(d) Ethoxyethane
›Reveal solutionSolution
CH3COOC2H5 = ethyl ethanoate (common name ethyl acetate).

The compound is an ester derived from ethanoic acid (CH3COOH) and ethanol (C2H5OH). An ester R-COO-R' is named as 'alkyl alkanoate':

The alkyl group from the alcohol part (C2H5) -> ethyl

The acyl part CH3COO- comes from ethanoic acid -> ethanoate

So the IUPAC name is ethyl ethanoate. Its common name is ethyl acetate.

✓Final answer
$(b) Ethyl ethanoate.$

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Q.The IUPAC name for the compound shown (a benzene ring bearing –Cl at C-1, –NO2 on the carbon adjacent to –Cl, and –CH3 para to –Cl) is ______.

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