Q.An ion with mass number 56 contains 3 units of positive charge and 30.4% more neutrons than electrons. Assign the symbol to this ion.
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Start your 14-day free trial to unlock the full solution →The key is to relate the mass number, charge, and the given neutron–electron excess. Using the atomic number and the number of electrons , we set up equations from the charge and the neutron count. Solving gives , which corresponds to iron (Fe). The ion is .
Let’s unpack this step by step. The problem gives three pieces of information about an ion:
- Mass number
- Charge (so it has lost 3 electrons)
- Neutrons are 30.4% more than electrons.
We need to find the element and write its symbol with the charge.
1. Set up the variables
Let:
- = atomic number (number of protons)
- = number of electrons in the ion
- = number of neutrons
For a neutral atom, . But here the ion has a charge, meaning it has lost 3 electrons. So:
The mass number is the sum of protons and neutrons:
2. Translate the “30.4% more neutrons than electrons”
“30.4% more neutrons than electrons” means:
This is the crucial relation. Now substitute :
3. Use the mass number equation
We have . Replace :
Simplify:
So . That’s the atomic number of iron (Fe).
A common mistake is to treat “30.4% more neutrons than electrons” as (adding a number) rather than multiplying by . Percentages always mean a ratio, not a fixed quantity.
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