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NCERT Exemplar · Q49

Q.The points A(−2,1)A(-2,1), B(0,5)B(0,5), C(−1,2)C(-1,2) are collinear.

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The slopes differ (mAB=2m_{AB}=2, mBC=3m_{BC}=3) and the triangle area is 1≠01\neq 0, so the three points are NOT collinear — the given statement is false.

Solution

Three points are collinear if and only if the area of the triangle they form is zero, equivalently if and only if the slopes of any two of the segments are equal.

Slope test.

mAB=5−10−(−2)=42=2,mBC=2−5−1−0=−3−1=3.m_{AB}=\frac{5-1}{0-(-2)}=\frac{4}{2}=2,\qquad m_{BC}=\frac{2-5}{-1-0}=\frac{-3}{-1}=3.

Since mAB≠mBCm_{AB}\neq m_{BC}, the points do not lie on a single line.

Area test (confirmation).

Area=12∣xA(yB−yC)+xB(yC−yA)+xC(yA−yB)∣.\text{Area}=\frac12\big|x_A(y_B-y_C)+x_B(y_C-y_A)+x_C(y_A-y_B)\big|. …

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