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Exercise 9.3 · Q8

Q.Find angles between the lines 3 x+y=1\sqrt{3}\,x + y = 1 and x+3 y=1x + \sqrt{3}\,y = 1.

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The angle between two lines is found using the slopes. The slopes are −3-\sqrt{3} and −13-\frac{1}{\sqrt{3}}, and the acute angle between them is 30∘30^\circ (or π6\frac{\pi}{6} radians).

The key idea is simple: the angle between two lines depends only on their slopes. Once you have the slopes, you plug them into the tangent formula and solve for the angle. Let’s see why that formula works.

When two lines are drawn, they make four angles — two equal acute ones and two equal obtuse ones. The acute angle is what we usually mean by “the angle between the lines.” The formula comes from the difference of their directions: if a line makes an angle θ\theta with the x-axis, its slope is tan⁡θ\tan \theta. So if two lines have slopes m1m_1 and m2m_2, their direction angles are θ1=tan⁡−1m1\theta_1 = \tan^{-1} m_1 and θ2=tan⁡−1m2\theta_2 = \tan^{-1} m_2. The acute angle between them is ∣θ1−θ2∣|\theta_1 - \theta_2| (or its supplement, whichever is acute). Using the tangent subtraction identity gives:

tan⁡ϕ=∣m1−m21+m1m2∣\tan \phi = \left| \frac{m_1 - m_2}{1 + m_1 m_2} \right|

where ϕ\phi is the acute angle between the lines.

Now let’s apply this to the given lines.

  1. Find the slopes.

    For the first line: 3 x+y=1\sqrt{3}\,x + y = 1.

    Rewrite as y=−3 x+1y = -\sqrt{3}\,x + 1. So slope m1=−3m_1 = -\sqrt{3}.

    For the second line: x+3 y=1x + \sqrt{3}\,y = 1.

    Rewrite as 3 y=−x+1\sqrt{3}\,y = -x + 1, so y=−13 x+13y = -\frac{1}{\sqrt{3}}\,x + \frac{1}{\sqrt{3}}. Slope m2=−13m_2 = -\frac{1}{\sqrt{3}}.

  2. Plug into the formula.

    Compute m1−m2m_1 - m_2:

m1−m2=−3−(−13)=−3+13=−3+13=−23m_1 - m_2 = -\sqrt{3} - \left(-\frac{1}{\sqrt{3}}\right) = -\sqrt{3} + \frac{1}{\sqrt{3}} = \frac{-3 + 1}{\sqrt{3}} = -\frac{2}{\sqrt{3}}

The absolute value is 23\frac{2}{\sqrt{3}}.

Compute 1+m1m21 + m_1 m_2:

m1m2=(−3)(−13)=1m_1 m_2 = (-\sqrt{3})\left(-\frac{1}{\sqrt{3}}\right) = 1

So 1+m1m2=1+1=21 + m_1 m_2 = 1 + 1 = 2. …

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