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Worked Examples · Example 20

Q.Find xx if ∣3−640∣=∣3x2x−1∣\begin{vmatrix} 3 & -6 \\ 4 & 0 \end{vmatrix} = \begin{vmatrix} 3 & x^2 \\ x & -1 \end{vmatrix}.

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Evaluate both determinants, equate them, and solve the resulting cubic x3=−27x^3 = -27.

∣abcd∣=ad−bc.\begin{vmatrix} a & b \\ c & d \end{vmatrix} = ad - bc.

  1. Evaluate the left determinant:

∣3−640∣=(3)(0)−(−6)(4)=0+24=24.\begin{vmatrix} 3 & -6 \\ 4 & 0 \end{vmatrix} = (3)(0) - (-6)(4) = 0 + 24 = 24.

  1. Evaluate the right determinant: …

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