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ABC International School, Delhi has different wings Administrative Wing (W1), Primary Wing (W2), Middle Wing(W3) and Secondary Wing(W4) as shown in the diagram : [Diagram: layout of four wings — ADMINISTRATIVE WING (W1), PRIMARY WING (W2), MIDDLE WING (W3), SECONDARY WING (W4) — within the Delhi campus, plus a separate MUMBAI BRANCH block.] The school also has a branch in Mumbai. The school management wants to connect all the wings as well as all the computers of each wing (W1, W2, W3, W4). Distance between the wings are as follows :

W3 to W185 m
W1 to W240 m
W2 to W425 m
W4 to W3120 m
W3 to W2150 m
W1 to W4170 m

Number of computers in each of the wing :

W1125
W240
W342
W460

Based on the above specifications, answer the following questions :

(i) Suggest the topology and draw the most suitable cable layout for connecting all the wings of Delhi branch.

(ii) Suggest the kind of network required (out of LAN, MAN, WAN) for connecting

  1. Administrative Wing (W1) with Middle Wing (W3)
  2. Administrative Wing (W1) with the Mumbai branch.

(iii) Suggest the placement of the following devices with justification :

(a) Repeater

(b) Switch/Hub

(iv) Due to pandemic school had to adopt Online classes. Suggest the protocol that is used for sending the voice signals over internet. Also, give an example of an application of WWW that helped the teachers to send messages instantly to the students.

CBSECBSE Class XII Board 2022Subjective· 4mImportance★★★★★
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The most suitable topology for connecting the four wings of the Delhi campus is a Star topology with the Administrative Wing (W1) as the central hub, because it minimises cable length and centralises network management. The connection between W1 and W3 is a LAN, while the connection between W1 and the Mumbai branch is a WAN. A Repeater is needed between W3 and W4 (the longest distance), and a Switch/Hub is needed in each wing to connect its computers. For online classes, VoIP (Voice over Internet Protocol) is used for voice, and Email is the WWW application for instant messaging.


When a school wants to connect its different wings into a single, efficient network, the first decision is about the physical layout — the topology. Think of topology as the map of how cables run between buildings. The goal is to choose a layout that is reliable, cost-effective (uses the least cable), and easy to manage.

Looking at the distances given, the Administrative Wing (W1) sits at a convenient central point. It is 40 m from W2, 85 m from W3, and 170 m from W4. If we connect every wing directly to W1, we get a Star topology. The total cable length would be: 40 + 85 + 170 = 295 metres. Compare this to a Ring topology (which would require connecting W1→W2→W4→W3→W1, totalling 40 + 25 + 120 + 85 = 270 metres) or a Bus topology (which would run a single long cable past all wings, likely exceeding 300 m). While the Ring uses slightly less cable, the Star is far superior for a school network.

Note

In a Star topology, if one cable fails (say, the link to W2 breaks), only W2 loses connection. The rest of the network continues working. In a Ring, a single break can bring down the entire loop unless a special "self-healing" ring protocol is used — which is more complex and expensive.

The Star topology also makes it easy to add new wings later, and it centralises network management — all traffic flows through W1, where you can place the main switch and server. This is exactly what a school like ABC International needs.

For the cable layout, the most practical choice today is twisted pair cable (Cat 6 or higher) with RJ-45 connectors, because it supports high speeds (up to 1 Gbps or more) and is affordable. However, note that twisted pair has a maximum segment length of 100 metres. Look at the distances: W1 to W4 is 170 m, and W3 to W4 is 120 m — both exceed 100 m. So for those links, you would need a Repeater (see part iii) or use fibre optic cable, which can run kilometres without signal loss. A practical layout would be: use twisted pair for W1↔W2 (40 m) and W1↔W3 (85 m), and fibre optic for W1↔W4 (170 m) because it is the longest link.

Important

The Star topology with W1 as the centre is the most suitable because it balances cable cost, reliability, and ease of management. The cable layout should use twisted pair for shorter links and fibre optic for the longest link (W1–W4).


(ii) Kind of network required

  1. Administrative Wing (W1) with Middle Wing (W3) — These two wings are on the same campus in Delhi, separated by only 85 metres. They are within the same building or adjacent buildings. This is a classic Local Area Network (LAN). A LAN connects computers within a limited geographical area (like a school, office, or home) and is owned and managed by the organisation itself.
  2. Administrative Wing (W1) with the Mumbai branch — Mumbai is in a different city, hundreds of kilometres away. This is a Wide Area Network (WAN). A WAN connects computers across large geographical distances, often using leased telecommunication lines or the public internet. The school would need to subscribe to an internet service provider (ISP) and use technologies like VPN (Virtual Private Network) to securely connect the two campuses.
    Note

    A MAN (Metropolitan Area Network) would cover a city-sized area — say, connecting two schools in different parts of Delhi. But Mumbai is a different city entirely, so it is definitely a WAN.


(iii) Placement of devices with justification

(a) Repeater — A repeater is a device that regenerates a signal, extending the maximum cable length. As noted, twisted pair cable has a 100-metre limit. The distance between W3 and W4 is 120 m, and between W1 and W4 is 170 m. So a repeater is needed on any link that exceeds 100 m. The most critical placement is between W3 and W4 (120 m) or between W1 and W4 (170 m). If using twisted pair for the W1–W4 link, you would place a repeater roughly halfway (around 85 m from W1). If using fibre optic, no repeater is needed because fibre can handle those distances easily. The textbook recommends placing a repeater wherever the cable length exceeds the maximum segment length. …

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