Q.(a)
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🔒 Start your 14-day free trial to unlock the full solution →Part (a)Concept understanding — Exponential Growth Rate
Exponential Growth Rate
A quantity grows exponentially when its rate of change is proportional to its current size: the more there is, the faster it grows. This differs sharply from linear growth, where a fixed amount is added each step. In exponential growth the quantity multiplies by the same factor over equal time intervals.
The differential equation
Let y(t) be the quantity and k>0 the proportionality constant. The rate law "rate of change proportional to the current amount" becomes
dtdy=ky.
This is a separable equation. Integrating,
∫ydy=∫kdt⟹log∣y∣=kt+C⟹y=y0ekt,
where y0=y(0) is the starting value. The constant k is the growth rate: a larger k means faster growth. (If k<0, the very same equation describes exponential decay.)
Reading the growth rate
Over each unit of time, y is multiplied by ek. So if the quantity doubles every unit of time, then ek=2, giving k=log2. This is how a stated doubling time is converted into the constant k.
Linear growth adds the same amount each step; exponential growth multiplies by the same factor. That is why an exponential quantity looks slow at first and then climbs steeply — the increase itself keeps getting bigger.
Where it appears …
Part (b)Concept understanding — Species Area Relationship
The Species Area Relationship: A First Look
Imagine you are walking through a small park near your home. You might spot a few birds, some insects, and a handful of plant species. Now imagine that same walk through a large forest reserve — hundreds of times bigger. Would you expect to see more kinds of birds, more types of insects, more varieties of trees? Almost certainly yes. That simple, intuitive observation is the seed of the Species Area Relationship.
What It Means
The Species Area Relationship (often abbreviated as SAR) is a pattern ecologists have observed across the natural world: as the area you sample increases, the number of species you find also increases. It is not a vague guess — it is a consistent, well-documented relationship that holds true for most groups of organisms, from plants and birds to insects and mammals.
Why does this happen? A larger area typically contains more habitats — forests, grasslands, wetlands, rocky outcrops — and each habitat supports its own set of species. A bigger area also tends to have more individuals, and with more individuals you are more likely to encounter rare species that might be absent from a small patch. In short, area acts as a rough proxy for ecological diversity and complexity.
Key Points to Remember
- The relationship is positive: bigger area → more species.
- It is not linear — doubling the area does not double the number of species. The increase slows down as area gets very large.
- The pattern holds across scales: from a single leaf (hosting tiny insects and fungi) to an entire continent.
The NCERT textbook for Class 12 Biology (Chapter 15, Biodiversity and Conservation) introduces this concept in the context of biodiversity patterns. It states that the relationship between species richness and area is described by a curve that rises rapidly at first and then flattens. The textbook does not require you to memorise any equation — only to understand the general trend and its implications.
Why It Matters
The Species Area Relationship is not just an academic curiosity. It has real-world consequences, especially for conservation.
- Designing protected areas: If you want to preserve a certain number of species, you need to know how much area is required. A small reserve may protect only a fraction of the region's biodiversity.
- Predicting extinctions: When a habitat is destroyed or fragmented, the remaining area shrinks. Using the SAR, ecologists can estimate how many species are likely to be lost as a result.
- Understanding island biology: The relationship was first studied on islands, where area is clearly defined and isolation limits immigration. The same logic applies to "habitat islands" — patches of forest surrounded by farmland, or national parks surrounded by cities. …
Part (a)
When resources are unlimited, every individual reproduces at its maximum rate and the population grows exponentially. The growth is described by dN/dt = rN, where N is population size and r is the intrinsic rate of natural increase (r = b - d). Integrating gives Nt = N0 e^(rt). Plotted against time this gives a J-shaped curve that rises ever more steeply, with no upper limit. …
Part (a): With unlimited resources a population grows exponentially - a J-shaped curve given by dN/dt = rN and Nt = N0 e^(rt). Part (b): Humboldt found that species richness increases with area, expressed as the Species-Area relationship S = C A^z (a straight line on log-log axes).
Part (a)
Concept - exponential growth. If food and space are unlimited and there is no competition, each organism reproduces to its full potential, so the population increases multiplicatively.
If N is the population density at time t, b the per-capita birth rate and d the per-capita death rate, then:
dN/dt = (b - d) N = rN
where r is the intrinsic rate of natural increase. Integrating this gives:
Nt = N0 e^(rt)
with N0 the initial population and e the base of natural logarithms. …
- CBSE 2025Set ANNUAL1 markQ.In a culture, the bacteria count is 1,00,000. The growth of bacteria is proportional to the number present. Let x be the number of bacteria at time t. Based on the above information, answer the following questions (assuming k to be the constant of proportionality): What is the relation between x and t?
›Reveal solutionSolution
Since the growth rate is proportional to the number present, x satisfies dtdx=kx, giving the exponential relation x=100000ekt.
The rate of growth of bacteria is proportional to the number of bacteria present at time t:
dtdx=kx
Separating variables and integrating,
∫xdx=∫kdt⟹lnx=kt+C
…
- CBSE 2025Set ANNUAL1 markQ.In a culture, the bacteria count is 1,00,000. The growth of bacteria is proportional to the number present. Let x be the number of bacteria at time t. Based on the above information, answer the following questions (assuming k to be the constant of proportionality): If the bacteria increased 10% in 2 hours, then find k.
›Reveal solutionSolution
Using x=100000ekt with a 10% increase at t=2 gives k=21ln(1.1)≈0.0477 per hour.
From the previous part, x=100000ekt.
The bacteria increase by 10% in 2 hours, so at t=2, x=100000+10% of 100000=110000.
110000=100000e2k
e2k=1.1
2k=ln(1.1) …
- CBSE 2025Set ANNUAL1 markQ.In a culture, the bacteria count is 1,00,000. The growth of bacteria is proportional to the number present. Let x be the number of bacteria at time t. Based on the above information, answer the following questions (assuming k to be the constant of proportionality): Find the time taken by the bacteria count increases from 1,00,000 to 2,00,000.
›Reveal solutionSolution
Doubling time follows from x=100000ekt: setting x=200000 gives t=kln2=ln1.12ln2≈14.55 hours.
We want the time t at which x=200000, starting from x=100000ekt:
200000=100000ekt
ekt=2
kt=ln2
t=kln2
Using k=21ln(1.1) from the previous part,
t=21ln(1.1)ln2=ln(1.1)2ln2
…
- CBSE 2025Set ANNUAL1 markMCQQ.The relation between species richness and area for a wide variety of taxa on a logarithmic scale is a(a) Rectangular hyperbola(b) Straight line(c) Sigmoid curve(d) Sine curve
›Reveal solutionSolution
On a log-log plot, species richness rises linearly with area (log S = log C + Z log A); on a normal (non-log) scale it is a rectangular hyperbola.
Ecologists have found that, within a region, species richness (S) increases with explored area (A), but only up to a certain limit; beyond this, the addition of new species with increasing area is minimal. On a normal (arithmetic) scale, this species-area relationship for a wide variety of taxa (plants, birds, fish) turns out to be a curve — specifically, a rectangular hyperbola.
…
- CBSE 2024Set 57/3/11 markMCQQ.The population growth curve applicable for a population growing in a geometric fashion, when the resources are not limiting in the habitat will be : (A) [graph: Population density vs Time — horizontal line] (B) [graph: Population density vs Time — straight rising line] (C) [graph: Population density vs Time — exponential (J-shaped) curve] (D) [graph: Population density vs Time — sigmoid (S-shaped) curve]
›Reveal solutionSolution
Geometric (exponential) growth with unlimited resources produces a J-shaped curve where population density accelerates upward without bound; the answer is (C).
When a population grows geometrically—meaning each individual produces a constant number of offspring per unit time—and resources are unlimited, we're describing exponential growth. The key insight is that the population doesn't just add a fixed number of individuals each generation; instead, it multiplies by a constant factor. A population of 100 that doubles becomes 200, then 400, then 800—the increment itself grows larger with each step because more parents produce more offspring.
Mathematically, this is captured by:
dN/dt = rN
where N is population size, t is time, and r is the intrinsic rate of increase. The solution is N(t) = N₀ e^{rt}, an exponential function. The hallmark of exponential growth is that the rate of increase is proportional to the current population size—bigger populations grow faster.
Now let's match this behavior to the graph options:
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Option (A): Horizontal line
A flat line means zero growth—the population size stays constant. This describes a population at equilibrium or with birth rate exactly matching death rate, not geometric growth.
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Option (B): Straight rising line
A linear increase means the population adds the same absolute number of individuals per unit time (arithmetic growth). If you gain 10 individuals per year regardless of population size, that's dN/dt = k (constant), not dN/dt = rN. This doesn't capture the accelerating nature of geometric growth.
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Option (C): J-shaped (exponential) curve
This curve starts slowly, then rises steeply, accelerating upward without leveling off. The slope gets steeper as time progresses because the population itself is growing—more individuals mean more reproduction. This is the signature of exponential growth when resources are unlimited and nothing checks the population. …
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- CBSE 2024Set ANNUAL1 markMCQQ.Observe the graph and select correct option (species richness vs. area, log-log scale, two curves A and B):(a) Line 'A' represents S = CA²(b) Line 'B' represents log C = log A + Z log S(c) Line A represents S = CA^Z(d) Line B represents log S = log Z + C log A
›Reveal solutionSolution
On a log-log plot, the species-area relationship follows the power law S = C·A^Z, which appears as a straight line; the plain (non-log) curve rises steeply then plateaus.
The species-area relationship describes how species richness (S) increases with sampled area (A) according to S = C·A^Z, where C is a constant (species density) and Z is the slope reflecting the rate of increase (regression coefficient). When plotted on ordinary axes, this relationship appears as a curve that rises steeply and then flattens (a rectangular-hyperbola-like shape) — matching curve A in the figure. When the same relationship is plotted on a log-log scale, taking logarithms of both sides gives l …
- CBSE 2023Set ANNUAL1 markQ.Write the function f(x), where f′(x)=f(x).
›Reveal solutionSolution
The differential equation f′(x)=f(x) is solved by separation of variables, giving the exponential function.
We have dxdf=f. Separating variables (assuming f=0):
fdf=dx
Integrating both sides:
ln∣f∣=x+c1
f(x)=Cex, where C=±ec1 is an arbitrary constant.
…
- CBSE 2022Set HE2201 markQ.Write the answer in one word/sentence: Types of curves are obtained in the growth of organism.
›Reveal solutionSolution
Populations can grow exponentially (J-curve, unlimited resources) or logistically (S-curve, limited resources/carrying capacity).
When resources (food, space) in a habitat are unlimited, a population grows exponentially, and a plot of population size against time gives a J-shaped curve (dN/dt = rN). In nature, resources are finite, so growth eventually slows as the population approaches the habitat's carrying capacity (K); a plot of this pattern gives an S-shaped (sigmoid) curve, described by the logistic growth equation …
- CBSE 2017Set ANNUAL1 markQ.In a given habitat, the maximum number possible for a species is called ________ of that species in that habitat.
›Reveal solutionSolution
The maximum population size that a given habitat can sustainably support is called the carrying capacity of that habitat for the species.
Every habitat has a finite amount of resources (food, space, nesting sites, etc.), so a population of a species cannot keep growing indefinitely within it. The largest population size that the habitat's resources can support — beyond which the population cannot be sustained (due to resource limitation, competition, increased mortality, etc.) — is termed the carrying capacity (K) of that habita …
- CBSE 2017Set ANNUAL1 markMCQQ.Z-values of a frugivorous bat species are given below. Which value is not applicable to continents ?(a) 0.6(b) 0.65(c) 0.20(d) 0.68
›Reveal solutionSolution
In the species-area relationship (log S = log C + Z log A), Z is usually 0.1-0.2 for small/regional areas but rises to about 0.6-1.2 when entire continents are compared, so 0.20 does not fit the continental range.
The naturalist Alexander von Humboldt found that within a region, species richness increases with explored area, but only up to a limit. On a log-log plot this relationship is a straight line described by log S = log C + Z log A, where S = species richness, A = area, Z = slope (regression coefficient) and C = the intercept.
Regardless of the taxonomic group or the region studied, the value of Z is remarkably consistent, falling in the narrow range of 0.1 to 0.2, when the analysis is confined to smaller, comparable areas within a region.
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