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Q.The colligative property used for the determination of molar mass of polymers and proteins is : (A) Osmotic pressure (B) Depression in freezing point (C) Relative lowering in vapour pressure (D) Elevation in boiling point

CBSECBSE Class XII Board 2023MCQ· 1mImportance★★★★★
✓ Free question

Osmotic pressure is the only colligative property with a magnitude large enough to measure accurately for high-molar-mass polymers and proteins in dilute solution. The answer is (A).

Why osmotic pressure works for macromolecules

Colligative properties depend on the number of solute particles, not their identity. For a given mass concentration, a high-molar-mass substance produces far fewer particles than a low-molar-mass one. This creates a measurement challenge: the colligative effect becomes vanishingly small.

Consider a 1%1\% solution of a polymer with molar mass M=100,000 g mol−1M = 100{,}000 \, \text{g mol}^{-1}. The molality is roughly 0.0001 mol kg−10.0001 \, \text{mol kg}^{-1}. Now compare the four colligative properties:

PropertyProportionality constantEffect for m≈0.0001m \approx 0.0001
Depression in freezing pointKf≈1.86 K kg mol−1K_f \approx 1.86 \, \text{K kg mol}^{-1} (water)ΔTf≈0.0002 K\Delta T_f \approx 0.0002 \, \text{K}
Elevation in boiling pointKb≈0.52 K kg mol−1K_b \approx 0.52 \, \text{K kg mol}^{-1} (water)ΔTb≈0.00005 K\Delta T_b \approx 0.00005 \, \text{K}
Relative lowering of vapour pressureΔpp0=χsolute\frac{\Delta p}{p^0} = \chi_{\text{solute}}≈0.000002\approx 0.000002
Osmotic pressureπ=CRT\pi = CRTπ≈2.5 kPa\pi \approx 2.5 \, \text{kPa} at 298 K298 \, \text{K}

The first three produce changes of order 10−410^{-4} to 10−610^{-6}, far below the precision of standard thermometers or manometers. Osmotic pressure, however, generates a measurable pressure difference even at very low concentrations.

Why the magnitude difference?

The key lies in the units and the nature of the measurement.

  1. Freezing-point depression and boiling-point elevation scale with molality through cryoscopic and ebullioscopic constants that are typically 11–2 K kg mol−12 \, \text{K kg mol}^{-1}. For macromolecules, m∼10−4m \sim 10^{-4} yields ΔT∼10−4 K\Delta T \sim 10^{-4} \, \text{K}, which requires extraordinarily sensitive thermometry.

  2. Vapour-pressure lowering is proportional to mole fraction. For dilute solutions of high-molar-mass solutes, χsolute∼10−6\chi_{\text{solute}} \sim 10^{-6}, making the relative change in vapour pressure unmeasurable with ordinary equipment.

  3. Osmotic pressure obeys π=CRT\pi = CRT, where CC is molar concentration. Even though CC is small, the gas constant R=8.314 J mol−1K−1R = 8.314 \, \text{J mol}^{-1} \text{K}^{-1} and room temperature T≈300 KT \approx 300 \, \text{K} combine to give RT≈2500 J mol−1=2500 Pa L mol−1RT \approx 2500 \, \text{J mol}^{-1} = 2500 \, \text{Pa L mol}^{-1}. A concentration of C=0.001 mol L−1C = 0.001 \, \text{mol L}^{-1} produces π≈2.5 kPa\pi \approx 2.5 \, \text{kPa}, easily measured with a simple manometer (a column height of about 25 cm25 \, \text{cm} of water).

Tip

Osmotic pressure is the only colligative property that remains experimentally accessible at the low particle concentrations characteristic of polymer and protein solutions.

Practical considerations

Proteins and synthetic polymers are often studied in aqueous solution at concentrations of 0.10.1–1%1\% by mass. At these concentrations:

  • A semipermeable membrane (permeable to solvent, impermeable to macromolecule) can be used to set up an osmotic cell.
  • The height difference in a U-tube or the pressure registered by a transducer gives π\pi directly.
  • From π=nVRT=wMVRT\pi = \frac{n}{V}RT = \frac{w}{MV}RT, rearranging gives M=wRTπVM = \frac{wRT}{\pi V}, allowing straightforward determination of molar mass.
Watch out

Attempting to use ΔTf\Delta T_f or ΔTb\Delta T_b for polymers leads to changes smaller than instrumental noise. Vapour-pressure methods face the same limitation and are further complicated by the need for precise manometry of very small pressure differences.

Summary of the reasoning

The determination of molar mass from a colligative property requires:

  • A measurable effect at the accessible concentration range.
  • Instrumentation capable of detecting that effect with reasonable precision.

For macromolecules, only osmotic pressure satisfies both criteria. The other three properties produce effects that are orders of magnitude too small.

✓Final answer

The correct option is (A) Osmotic pressure.

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