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NCERT Exemplar · Q5

Q.S is the surface of a lump of magnetic material.

(a) Lines of B are necessarily continuous across S.
(b) Some lines of B must be discontinuous across S.
(c) Lines of H are necessarily continuous across S.
(d) Lines of H cannot all be continuous across S.
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Because ∇⋅B⃗=0\nabla\cdot\vec{B}=0 always, B⃗\vec{B}-lines are continuous across the surface of a magnetic lump. But H⃗\vec{H} is sourced by magnetic poles at that surface, so H⃗\vec{H}-lines cannot all be continuous. Correct options: (a) and (d).

Concept understanding. The two magnetic fields obey

∇⋅B⃗=0,B⃗=μ0(H⃗+M⃗),∇⋅H⃗=−∇⋅M⃗.\nabla\cdot\vec{B}=0,\qquad \vec{B}=\mu_0(\vec{H}+\vec{M}),\qquad \nabla\cdot\vec{H}=-\nabla\cdot\vec{M}.

The first says B⃗\vec{B} has no sources or sinks: its field lines are always closed loops and its normal component is continuous across any boundary,

Bn,in=Bn,out.B_{n,\text{in}} = B_{n,\text{out}}.

Inside the material M⃗≠0\vec{M}\neq 0; just outside M⃗=0\vec{M}=0. So M⃗\vec{M} drops abruptly across SS, and this jump acts as an effective surface pole density σm=M⃗⋅n^\sigma_m = \vec{M}\cdot\hat{n}. From H⃗=B⃗/μ0−M⃗\vec{H}=\vec{B}/\mu_0-\vec{M}, the normal component of H⃗\vec{H} jumps:

Hn,out−Hn,in=Mn=M⃗⋅n^.H_{n,\text{out}} - H_{n,\text{in}} = M_n = \vec{M}\cdot\hat{n}.

Testing each option.

  • (a) Lines of B⃗\vec{B} are necessarily continuous across SS (normal component continuous; B⃗\vec{B}-lines are closed). Correct. …

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