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Exercises · 10.9

Q.Light of wavelength 5000 A˚5000\ \text{Å} falls on a plane reflecting surface. What are the wavelength and frequency of the reflected light? For what angle of incidence is the reflected ray normal to the incident ray?

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Reflection never changes wavelength or frequency, so the reflected light is still 5000 A˚5000\ \text{Å} at 6×1014 Hz6\times10^{14}\ \text{Hz}; for the reflected ray to be normal (perpendicular) to the incident ray, the angle of incidence must be 45∘45^\circ.

Step 1: Wavelength and frequency of the reflected light

Reflection occurs at the boundary of the same medium the light was travelling in — there is no change of medium, so both wavelength and frequency are unchanged:

λreflected=λincident=5000 A˚=5000×10−10 m\lambda_{reflected} = \lambda_{incident} = 5000\ \text{Å} = 5000 \times 10^{-10}\ \text{m}

The frequency follows from ν=c/λ\nu = c/\lambda:

ν=3×108 m s−15000×10−10 m=6×1014 Hz\nu = \frac{3\times10^{8}\ \text{m s}^{-1}}{5000\times10^{-10}\ \text{m}} = 6\times10^{14}\ \text{Hz}

Step 2: Angle of incidence for a perpendicular reflected ray

By the law of reflection, the angle of incidence ii equals the angle of reflection rr, both measured from the normal, with the incident and reflected rays on opposite sides of the normal. …

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