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Exercise 2.1 · Q11

Q.An ant is moving around a circular path of radius 3.5 cm and takes 3 seconds to complete 1 revolution. Find the average speed and average velocity?

Chandigarh CbseNCERTSubjective· 3mImportance★★★★★est
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Over one full lap the ant covers 2222 cm of path but returns to its starting point, so its speed is nonzero but its velocity is zero.

Average speed=total distancetotal time,Average velocity=net displacementtotal time,Circumference=2πr\text{Average speed}=\dfrac{\text{total distance}}{\text{total time}},\qquad \text{Average velocity}=\dfrac{\text{net displacement}}{\text{total time}},\qquad \text{Circumference}=2\pi r

Given: radius r=3.5r=3.5 cm, time for one revolution T=3T=3 s (use π=227\pi=\frac{22}{7}).

  1. Distance covered in one revolution = circumference of the circle:

d=2πr=2×227×3.5=2×227×72=22 cmd = 2\pi r = 2\times\dfrac{22}{7}\times3.5 = 2\times\dfrac{22}{7}\times\dfrac{7}{2} = 22\ \text{cm}

  1. Average speed:

speed=dT=223=7.3‾≈7.33 cm/s\text{speed} = \dfrac{d}{T} = \dfrac{22}{3} = 7.\overline{3}\approx 7.33\ \text{cm/s}

  1. Since the ant completes exactly one full revolution, it returns to its starting point, so the net displacement is: …

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