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Exercise 13.1 · Q1

Q.Find the mean deviation about the mean for the following data: 4, 7, 8, 9, 10, 12, 13, 17

Chandigarh CbseNCERTSubjective· 3mImportance★★★★★est
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Mean deviation about the mean measures the average absolute distance of each observation from the arithmetic mean. For this dataset, the mean is 1010 and the mean deviation is 3\boxed{3}.

Understanding Mean Deviation About Mean

Mean deviation tells us how spread out the data is from its center. Unlike variance (which squares deviations), mean deviation uses absolute values, making it more intuitive: it literally answers "on average, how far is each data point from the mean?"

The formula is:

Mean Deviation=∑∣xi−xˉ∣n\text{Mean Deviation} = \frac{\sum |x_i - \bar{x}|}{n}

where xˉ\bar{x} is the mean and nn is the number of observations.

Step-by-Step Solution

1. Calculate the arithmetic mean

We have n=8n = 8 observations: 4,7,8,9,10,12,13,174, 7, 8, 9, 10, 12, 13, 17.

xˉ=4+7+8+9+10+12+13+178=808=10\bar{x} = \frac{4 + 7 + 8 + 9 + 10 + 12 + 13 + 17}{8} = \frac{80}{8} = 10

2. Find the absolute deviation of each observation from the mean

For each data point xix_i, we compute ∣xi−10∣|x_i - 10|:

| xix_i | xi−xˉx_i - \bar{x} | ∣xi−xˉ∣|x_i - \bar{x}| |

|-------|-----------------|-------------------|

| 4 | 4−10=−64 - 10 = -6 | 6 |

| 7 | 7−10=−37 - 10 = -3 | 3 |

| 8 | 8−10=−28 - 10 = -2 | 2 |

| 9 | 9−10=−19 - 10 = -1 | 1 |

| 10 | 10−10=010 - 10 = 0 | 0 |

| 12 | 12−10=212 - 10 = 2 | 2 |

| 13 | 13−10=313 - 10 = 3 | 3 |

| 17 | 17−10=717 - 10 = 7 | 7 |

Tip

Notice the symmetry: deviations below the mean (negative) and above the mean (positive) both contribute positively to the mean deviation because we take absolute values.

3. Sum the absolute deviations

∑∣xi−xˉ∣=6+3+2+1+0+2+3+7=24\sum |x_i - \bar{x}| = 6 + 3 + 2 + 1 + 0 + 2 + 3 + 7 = 24

4. Divide by the number of observations

Mean Deviation=248=3\text{Mean Deviation} = \frac{24}{8} = 3

This tells us that, on average, each observation is 33 units away from the mean of 1010.

✓Final answer

The mean deviation about the mean for the given data is 3\boxed{3}.

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