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Exercises · 6.14

Q.To maintain a rotor at a uniform angular speed of 200 rad s−1^{-1}, an engine needs to transmit a torque of 180 N m. What is the power required by the engine? (Note: uniform angular velocity in the absence of friction implies zero torque. In practice, applied torque is needed to counter frictional torque). Assume that the engine is 100% efficient.

Chandigarh CbseNCERTSubjective· 2mImportance★★★★★est
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The power required by an engine to maintain a uniform angular speed against a given torque is the product of the torque and the angular speed. The required power is 36000 W\boxed{36000 \text{ W}}.

When an engine maintains a rotor at a uniform angular speed, it means there is no angular acceleration. In an ideal scenario without friction, no torque would be needed once the desired speed is reached. However, in practice, there's always some frictional torque opposing the motion. The engine must apply an equal and opposite torque to precisely counteract this frictional torque, thereby keeping the net torque zero and the angular speed constant. The power required by the engine is the rate at which it does work to overcome this frictional resistance.

This concept is directly analogous to linear motion: if you push a block at a constant velocity across a rough surface, you need to apply a force equal to the frictional force. The power you expend is the product of this force and the velocity (P=FvP = Fv). In rotational motion, force is replaced by torque (τ\tau), and linear velocity is replaced by angular speed (ω\omega).

  1. Identify the given quantities:

    We are given the uniform angular speed of the rotor and the torque the engine needs to transmit.

    • Angular speed, ω=200 rad s−1\omega = 200 \text{ rad s}^{-1}
    • Torque, τ=180 N m\tau = 180 \text{ N m}
  2. Recall the formula for power in rotational motion:

    The power (PP) delivered by a rotating object or an engine applying torque is the product of the torque (τ\tau) and the angular speed (ω\omega).

    P=τωP = \tau \omega …

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