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Worked Examples · Example 28

Q.An asset costing ₹10,000 is expected to have a useful life of 4 years and a scrap value of zero. Find the annual depreciation charge using the sum-of-the-years digits method.

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The sum-of-the-years' digits method accelerates depreciation by applying a decreasing fraction to the depreciable amount each year. For a ₹10,000 asset with a 4-year life and zero scrap, the annual charges are ₹4,000, ₹3,000, ₹2,000, and ₹1,000.

The sum-of-the-years' digits method is an accelerated depreciation technique. Unlike straight-line depreciation, which spreads the cost evenly, this method allocates a larger portion of the asset's cost to the earlier years of its useful life. The logic is that many assets lose more value in their first few years of use — think of a new car's steep initial depreciation.

The method works by creating a fraction for each year. The denominator of this fraction is the sum of the digits of the asset's useful life. For a 4-year life, that sum is 1+2+3+4=101 + 2 + 3 + 4 = 10. The numerator for each year is the remaining useful life at the start of that year. So in year 1, the fraction is 410\frac{4}{10}; in year 2, 310\frac{3}{10}; in year 3, 210\frac{2}{10}; and in year 4, 110\frac{1}{10}.

You multiply each year's fraction by the depreciable amount — which is the original cost minus the scrap value. Here, scrap value is zero, so the depreciable amount is simply ₹10,000.

Let's work through each year:

  1. Year 1: Remaining life at start = 4 years. Fraction = 410\frac{4}{10}. Depreciation charge = 410×10,000=4,000\frac{4}{10} \times 10,000 = 4,000.
  2. Year 2: Remaining life at start = 3 years. Fraction = 310\frac{3}{10}. Depreciation charge = 310×10,000=3,000\frac{3}{10} \times 10,000 = 3,000.
  3. Year 3: Remaining life at start = 2 years. Fraction = 210\frac{2}{10}. Depreciation charge = 210×10,000=2,000\frac{2}{10} \times 10,000 = 2,000.
  4. Year 4: Remaining life at start = 1 year. Fraction = 110\frac{1}{10}. Depreciation charge = 110×10,000=1,000\frac{1}{10} \times 10,000 = 1,000.

Notice that the charges decrease by a constant amount each year — here, by ₹1,000. That's a neat property of this method when scrap value is zero. …

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