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NCERT Exemplar · Q11

Q.The longest side of a triangle is twice the shortest side and the third side is 22 cm longer than the shortest side. If the perimeter of the triangle is more than 166166 cm then find the minimum length of the shortest side.

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Letting the shortest side be xx cm, the perimeter condition x+2x+(x+2)>166x + 2x + (x+2) > 166 simplifies to x>41x > 41. Since no integer restriction is given, the shortest side must be any real length greater than 4141 cm.

This is a direct translation problem: turn the verbal description of the three sides into algebraic expressions in one variable, then apply the perimeter condition as an inequality.

Step-by-step solution:

  1. Define the variable. Let the shortest side be xx cm (x>0x > 0).
  2. Express the other two sides. The longest side is twice the shortest: 2x2x cm. The third side is 22 cm longer than the shortest: x+2x + 2 cm.
  3. Write the perimeter condition. Perimeter =x+2x+(x+2)=4x+2= x + 2x + (x+2) = 4x + 2. The problem says this is more than 166166 cm:

4x+2>1664x + 2 > 166

  1. Solve the inequality. 4x>164  ⟹  x>414x > 164 \implies x > 41 …

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