Skip to content
Miscellaneous Exercise · Q10

Q.5(2x−7)−3(2x+3)≤05(2x - 7) - 3(2x + 3) \le 0, 2x+19≤6x+472x + 19 \le 6x + 47

Chhattisgarh CgbseTextbookSubjective· 2mImportance★★★★★
52% · 49/94 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Solve each inequality separately, then find the intersection of their solution sets. The system is satisfied when x≥−7x \ge -7.

Linear inequalities behave almost exactly like equations when you solve them, with one crucial exception: multiplying or dividing both sides by a negative number reverses the inequality sign. When you have a system of inequalities, you need both conditions to hold simultaneously, so you take the overlap (intersection) of the individual solution sets.

Let's tackle each inequality in turn, then combine the results.

First inequality: 5(2x−7)−3(2x+3)≤05(2x - 7) - 3(2x + 3) \le 0

  1. Expand the brackets

    10x−35−6x−9≤010x - 35 - 6x - 9 \le 0

  2. Combine like terms

    (10x−6x)+(−35−9)≤0(10x - 6x) + (-35 - 9) \le 0

    4x−44≤04x - 44 \le 0

  3. Isolate xx

    Add 4444 to both sides:

    4x≤444x \le 44

    Divide by 44 (positive, so the inequality stays the same):

    x≤11x \le 11

The first inequality gives us x≤11x \le 11.

Second inequality: 2x+19≤6x+472x + 19 \le 6x + 47

  1. Collect xx terms on one side

    Subtract 2x2x from both sides:

    19≤4x+4719 \le 4x + 47

  2. Isolate the xx term

    Subtract 4747 from both sides:

    19−47≤4x19 - 47 \le 4x

    −28≤4x-28 \le 4x

  3. Solve for xx

    Divide by 44:

    −7≤x-7 \le x

    which we write as x≥−7x \ge -7 …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.