Q.Draw a league fixture for 7 teams by the Cyclic method. Calculate the total number of matches and the number of rounds, and show the pairings round by round.
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Start your 14-day free trial to unlock the full solution →For 7 teams in a league tournament using the Cyclic method, there will be 21 matches played over 7 rounds, with one team getting a bye in each round.
A league tournament, also known as a round-robin tournament, is a competition format where every participant plays against every other participant at least once. This method ensures that the best team is identified through consistent performance, as luck plays a minimal role compared to a knock-out format. The Cyclic method is one way to draw fixtures for such a tournament, particularly useful for ensuring a systematic rotation of opponents.
When the number of teams (N) is odd, as in this case with N=7, a 'bye' is introduced to facilitate the rotation. This effectively makes the total number of entities (teams + bye) even, allowing for a smooth cyclic movement. The team paired with the 'bye' in a given round does not play a match in that round.
Calculations
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Total number of matches:
In a league tournament where each team plays every other team once, the total number of matches is calculated using the formula:
Total matches = (N × (N - 1))/2
Substituting N=7:
- Total matches = (7 × (7 - 1))/2
- Total matches = (7 × 6)/2
- Total matches = 42/2
- Total matches = 21
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Number of rounds:
For an odd number of teams (N), the number of rounds in a league tournament is equal to N.
- Number of rounds = N
- Number of rounds = 7
Fixture Drawing by Cyclic Method
For N=7 teams, we introduce a 'Bye' (B) to make the total number of entities 8. We fix the 'Bye' at the top position and arrange the teams (1, 2, 3, 4, 5, 6, 7) in a clockwise direction. In each subsequent round, the teams (1-7) rotate one position clockwise, while the 'Bye' remains fixed. The team paired with the 'Bye' in a round gets a rest. …
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