Q.The number of arbitrary constants in the particular solution of a differential equation of third order are: (A) 3 (B) 2 (C) 1 (D) 0
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Start your 14-day free trial to unlock the full solution →The particular solution of a differential equation has zero arbitrary constants — all constants are eliminated when initial or boundary conditions are applied to the general solution. The correct answer is (D) 0.
Why the answer is zero — the core idea
The confusion here usually comes from mixing up the general solution with the particular solution. A third-order differential equation has a general solution containing three arbitrary constants (because you need to integrate three times). But the question asks about the particular solution — that’s a completely different beast.
A particular solution is obtained by plugging specific initial or boundary conditions into the general solution, which fixes every constant to a definite number. Once those constants become numbers, they are no longer “arbitrary.” So the count drops to zero.
Let’s walk through it step by step.
- General solution of a third-order DE A third-order differential equation involves the third derivative. Solving it requires three integrations, each introducing one arbitrary constant. So the general solution looks like:
where are arbitrary constants. That’s three constants — but this is not the particular solution.
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What makes a solution “particular”?
To get a particular solution, you need extra information — typically three initial conditions (like , , ) or boundary conditions. You substitute these into the general solution (and its derivatives) to solve for .
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Constants become fixed numbers
After applying the conditions, each constant takes a specific numerical value. For example, you might get , , . These are no longer “arbitrary” — they are determined uniquely by the problem. …
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