Q.Write Ampere's circuital law and by using this law derive the expression for intensity of magnetic field inside a current-carrying solenoid. OR Explain moving coil galvanometer on the following points:
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Start your 14-day free trial to unlock the full solution →Ampere's law equates the line integral of B around a closed loop to μ₀ times the enclosed current; using a rectangular loop partly inside and partly outside a long solenoid gives the uniform interior field B = μ₀nI.
Ampere's circuital law: The line integral of the magnetic field around any closed loop is equal to μ₀ times the total current enclosed by that loop:
Field inside a long current-carrying solenoid:
Consider a long solenoid with n turns per unit length, carrying a steady current I. For an ideal long solenoid, the magnetic field inside is strong, uniform, and directed along the axis, while the field just outside the solenoid is negligibly small (≈ 0).
Choose a rectangular Amperian loop PQRS such that:
- Side PQ (length L) lies inside the solenoid, parallel to the axis, where the field is uniform and equal to B.
- Side RS lies outside the solenoid, where the field is ≈ 0.
- Sides QR and SP are perpendicular to the axis (partly inside, partly outside); along these, the magnetic field (wherever nonzero, i.e. inside) is perpendicular to , so on these sides, and outside the field is ≈ 0 anyway. …
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