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Q.A solenoid of length 0.5 m has a radius of 1 cm and has 500 turns. It carries current of 5 A. What is the magnitude of the magnetic field inside the solenoid? OR Out of an ammeter, voltmeter and galvanometer, which one has lowest and highest resistance? Justify your response.

Himachal HpboseHPBOSE Plus Two Board 2026Subjective· 2mImportance★★★★★
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Using B=μ0nIB=\mu_0 n I for an ideal solenoid, the field inside works out to about 6.28×10−36.28\times10^{-3} T.

Given: length l=0.5l = 0.5 m, number of turns N=500N = 500, current I=5I = 5 A. (The radius, 1 cm, is not needed — for an ideal long solenoid the interior field does not depend on the radius, only on the number of turns per unit length and the current.)

Turns per unit length:

n=Nl=5000.5=1000 turns/mn = \frac{N}{l} = \frac{500}{0.5} = 1000\ \text{turns/m}

Magnetic field inside the solenoid: …

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