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Worked Examples · Example 7

Q.A invests 80008000 rupees in a business. After 66 months he withdraws 20002000 rupees. B invests 60006000 rupees for the whole year. If the annual profit is 26002600 rupees, find each partner's share.

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A's capital does not stay fixed for the year — it is 80008000 rupees for the first 66 months and then 8000−2000=60008000 - 2000 = 6000 rupees for the last 66 months — so his contribution must be found stretch by stretch.

Step 1 — A's total capital-months. A=(8000×6)+(6000×6)=48000+36000=84000.A = (8000 \times 6) + (6000 \times 6) = 48000 + 36000 = 84000.

Step 2 — B's total capital-months. B keeps 60006000 rupees for all 1212 months: B=6000×12=72000.B = 6000 \times 12 = 72000.

Step 3 — form and reduce the ratio. 84000:72000=7:6(dividing both by 12000).84000 : 72000 = 7 : 6 \quad (\text{dividing both by } 12000).

Step 4 — value of one part. Total parts =7+6=13= 7 + 6 = 13, so one part=260013=200 rupees.\text{one part} = \frac{2600}{13} = 200 \text{ rupees}. …

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