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Business Mathematics and Statistics · Ch 4 — Functions

Ordered Pairs and the Cartesian Product

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Ordered Pairs and the Cartesian Product

Before a relation or a function can be defined precisely, we need a way of pairing up elements from two sets so that the order in which they are written matters. An ordered pair (a,b)(a, b) consists of a first element aa and a second element bb, written in that fixed order; two ordered pairs (a,b)(a,b) and (c,d)(c,d) are equal only when a=ca=c and b=db=d. This is the key difference from an ordinary set {a,b}\{a,b\}, where {a,b}\{a,b\} and {b,a}\{b,a\} are the same set — but (a,b)(a,b) and (b,a)(b,a) are, in general, two different ordered pairs.

Given two non-empty sets AA and BB, the Cartesian product A×BA \times B is the set of all ordered pairs whose first element comes from AA and whose second element comes from BB:

A×B={(a,b):a∈A, b∈B}A \times B = \{(a,b) : a \in A,\ b \in B\}

If AA has mm elements and BB has nn elements, then A×BA \times B has exactly m×nm \times n ordered pairs — every element of AA is paired once with every element of BB. For example, if A={1,2}A=\{1,2\} and B={x,y,z}B=\{x,y,z\}, then

A×B={(1,x),(1,y),(1,z),(2,x),(2,y),(2,z)}A \times B = \{(1,x),(1,y),(1,z),(2,x),(2,y),(2,z)\}

which has 2×3=62 \times 3 = 6 ordered pairs, exactly as the counting rule predicts. In general A×B≠B×AA \times B \neq B \times A unless A=BA=B, because reversing the order of every pair produces a genuinely different set of pairs.

The Odisha CHSE Std-11 Business Mathematics & Statistics syllabus builds the whole chapter on Functions on top of this one idea — a relation, and later a function, is nothing more than a carefully chosen subset of a Cartesian product A×BA \times B.

Definition 1Ordered Pair

A pair of elements (a,b)(a,b) written in a fixed order, so that (a,b)=(c,d)(a,b) = (c,d) if and only if a=ca=c and b=db=d.

Definition 2Cartesian Product $A \times B$

The set of all ordered pairs (a,b)(a,b) with a∈Aa \in A and b∈Bb \in B. If AA has mm elements and BB has nn elements, then n(A×B)=m×nn(A \times B) = m \times n.