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Exercises · 18.3

Q.Explain the following processes:

(a) Polarisation of the membrane of a nerve fibre
(b) Depolarisation of the membrane of a nerve fibre
(c) Transmission of a nerve impulse across a chemical synapse
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Polarisation sets up a neuron's resting charge, depolarisation reverses that charge to make the impulse, and a chemical synapse ferries the signal to the next neuron using neurotransmitters across a tiny gap.

  1. Polarisation of the membrane of a nerve fibre A neuron at rest is not electrically neutral — its membrane is kept charged, and this is what makes the cell excitable. The membrane is selectively (differentially) permeable, carrying ion channels that let only particular ions through. At rest it is comparatively more permeable to potassium ions and almost impermeable to sodium ions, and also impermeable to the large negatively charged proteins in the axoplasm. So the inside holds a high concentration of potassium and proteins with little sodium, while the outside fluid has high sodium and low potassium. These gradients are actively maintained by the sodium–potassium pump, which moves three sodium ions out for every two potassium ions in. The outcome is that the outer surface of the membrane carries a positive charge and the inner surface a negative charge — the membrane is polarised, and this charge difference is the resting potential.
  2. Depolarisation of the membrane of a nerve fibre Depolarisation is the sudden collapse and reversal of that resting charge. When a stimulus is applied at a point on the polarised membrane, the membrane there suddenly becomes freely permeable to sodium ions. Sodium ions rush inward in a rapid influx, and this reverses the polarity at that site: the outer surface now becomes negatively charged and the inner surface positively charged. The membrane at that point is said to be depolarised, and the potential difference produced across it is the action potential — which is precisely what we call the nerve impulse.
    Note

    This rise in sodium permeability is very short-lived. It is soon followed by a rise in potassium permeability; potassium diffuses outward and restores the resting potential, making that part of the fibre ready to respond again.

  3. Transmission of a nerve impulse across a chemical synapse At a chemical synapse the pre-synaptic and post-synaptic neurons are not in direct contact — their membranes are separated by a narrow, fluid-filled gap called the synaptic cleft. Since electricity cannot jump this gap, the signal is carried across by chemical messengers, the neurotransmitters, which are stored in synaptic vesicles in the axon terminal. The transmission proceeds as follows:
  • An impulse, in the form of an action potential, travels down the pre-synaptic neuron and arrives at its axon terminal.
  • Its arrival, aided by the entry of calcium ions, moves the synaptic vesicles towards the pre-synaptic membrane.
  • The vesicles fuse with the membrane and release their neurotransmitters into the synaptic cleft.
  • The neurotransmitters diffuse across the cleft and bind to specific receptors on the post-synaptic membrane.
  • This binding opens ion channels, ions move across the post-synaptic membrane, and a new potential is generated in the post-synaptic neuron — regenerating the signal on the far side.
Important

The new potential produced may be excitatory (making the next neuron more likely to fire) or inhibitory (making it less likely to fire). This ability to either excite or inhibit is a key feature of chemical synapses and is central to how the nervous system processes information.

✓Final answer

In short, polarisation is the resting charged state of the membrane, depolarisation is its stimulus-driven reversal that forms the impulse, and a chemical synapse relays that impulse to the next neuron by releasing neurotransmitters across the synaptic cleft.

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