Q.A proton and an alpha particle have equal momentum. The ratio of their kinetic energies and the ratio of the de Broglie wavelengths associated with them respectively are : (A) (B) (C) (D)
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Start your 14-day free trial to unlock the full solution →For equal momentum, kinetic energy is inversely proportional to mass, and de Broglie wavelength is directly proportional to mass. Since the alpha particle has 4 times the mass of a proton, the ratio of kinetic energies is and the ratio of wavelengths is . The correct option is (C).
The key to this problem lies in two fundamental relationships: the de Broglie wavelength and the connection between kinetic energy and momentum. When two particles have the same momentum, their de Broglie wavelengths become equal — that part is immediate. The kinetic energy, however, depends on mass because , so the lighter particle has more kinetic energy.
Let’s work through it systematically.
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Recall the de Broglie wavelength formula.
Every moving particle has a wavelength associated with it, given by , where is Planck’s constant and is the linear momentum. This is a direct consequence of wave-particle duality — the more momentum a particle has, the shorter its wavelength.
Since the problem states that the proton and alpha particle have equal momentum, we can write:
Therefore:
Because , the two wavelengths are identical:
- Now find the kinetic energy ratio. Kinetic energy is related to momentum by:
This comes from combining with . For equal momentum, the kinetic energy is inversely proportional to mass — a heavier particle moving with the same momentum must be slower, so it has less kinetic energy.
For the proton (mass ) and alpha particle (mass ):
- Know the masses involved. …
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