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Worked Examples · Example 3

Q.Divide ₹43,500 into two parts so that the simple interest on the first part when deposited for one year at 9% per annum and that on the second part when deposited for 2 years at 10% per annum in a bank are the same.

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Set the two simple-interest expressions equal and solve for the split of ₹43,500.

SI=P×R×T100SI=\dfrac{P\times R\times T}{100}, where PP is the part deposited, RR the rate (%), TT the time (years).

Given: Total =₹43,500=₹43{,}500. Part 1: T=1T=1 yr, R=9%R=9\%. Part 2: T=2T=2 yr, R=10%R=10\%. SI on both parts is equal.

  1. Let the first part be xx; the second part is (43500−x)(43500-x).
  2. SI on first part: SI1=x×9×1100=0.09xSI_1=\dfrac{x\times9\times1}{100}=0.09x.
  3. SI on second part: SI2=(43500−x)×10×2100=0.20(43500−x)SI_2=\dfrac{(43500-x)\times10\times2}{100}=0.20(43500-x).
  4. Set SI1=SI2SI_1=SI_2: 0.09x=0.20(43500−x)=8700−0.20x0.09x=0.20(43500-x)=8700-0.20x …

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