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Worked Examples · Example 45
Q.

Calculate the Spearman's rank correlation for the below given data:

IQ99120981021231058511011790
EQ30304516251724265
Dnh Dd CbseNCERTSubjective· 5mImportance★★★★★est
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Ranking the 10 individuals' IQ and EQ scores and applying Spearman's formula gives ρ≈−0.115\rho\approx-0.115, indicating almost no linear relationship (a very weak negative tendency) between IQ rank and EQ rank in this sample.

ρ=1−6∑di2n(n2−1)\rho=1-\dfrac{6\sum d_i^2}{n(n^2-1)}, where di=R(xi)−R(yi)d_i=R(x_i)-R(y_i) is the difference between the ranks of the ithi^{th} pair, and nn = number of pairs.

  1. Rank the IQ values in descending order (rank 11 = highest IQ); all 10 values are distinct, so there are no ties:
Student12345678910
IQ99120981021231058511011790
EQ30304516251724265
R(IQ)R(IQ)72861510439
R(EQ)R(EQ)91021746538
d=R(IQ)−R(EQ)d=R(IQ)-R(EQ)-2-865-614-101
d2d^2464362536116101
  1. Rank EQ the same way (rank 11 = highest EQ); all 10 values distinct, no ties.
  2. Check: both rank columns sum to n(n+1)2=10(11)2=55\dfrac{n(n+1)}{2}=\dfrac{10(11)}{2}=55 ✓ (7+2+8+6+1+5+10+4+3+9=557+2+8+6+1+5+10+4+3+9=55; 9+10+2+1+7+4+6+5+3+8=559+10+2+1+7+4+6+5+3+8=55). …

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