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Worked Examples · Example 11

Q.Speeds of two cars, A and B is in the ratio Speed of car ASpeed of car B=xy\dfrac{Speed\ of\ car\ A}{Speed\ of\ car\ B} = \dfrac{x}{y}. Find the relation between the time taken by car A and car B, given that speed = distancetime\dfrac{distance}{time}.

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For a fixed distance, speed and time are inversely proportional, so if the speeds of A and B are in the ratio x:yx:y, their times are in the ratio y:xy:x.

speed=distancetime\text{speed} = \dfrac{\text{distance}}{\text{time}}

For a given (same) distance dd covered by both cars: d=SpeedA⋅tA=SpeedB⋅tBd = \text{Speed}_A \cdot t_A = \text{Speed}_B \cdot t_B.

Given: Speed of car ASpeed of car B=xy\dfrac{\text{Speed of car A}}{\text{Speed of car B}} = \dfrac{x}{y}; both cars travel the same distance dd.

  1. Write the distance equation for each car:

d=SpeedA tAd=SpeedB tBd = \text{Speed}_A\, t_A \qquad d = \text{Speed}_B\, t_B

  1. Since both equal dd, set them equal:

SpeedA tA=SpeedB tB\text{Speed}_A\, t_A = \text{Speed}_B\, t_B

  1. Rearrange to isolate the speed ratio:

SpeedASpeedB=tBtA\dfrac{\text{Speed}_A}{\text{Speed}_B} = \dfrac{t_B}{t_A}

  1. Substitute the given ratio SpeedASpeedB=xy\dfrac{\text{Speed}_A}{\text{Speed}_B}=\dfrac{x}{y}:

xy=tBtA ⇒ tAtB=yx\dfrac{x}{y} = \dfrac{t_B}{t_A} \ \Rightarrow\ \dfrac{t_A}{t_B} = \dfrac{y}{x}

  1. Self-check: if A is faster (x>yx>y), the ratio tA/tB=y/x<1t_A/t_B=y/x<1 means A takes less time than B — consistent with a faster car finishing sooner over the same distance. ✓
✓Final answer

tA:tB=y:xt_A : t_B = y : x (equivalently x tA=y tBx\,t_A = y\,t_B) — time is inversely proportional to speed for a fixed distance.

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