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Worked Examples · Example 30

Q.How many arrangements of the letters of word SOCIOLOGICAL are there if A and G are adjacent.

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SOCIOLOGICAL has 12 letters (S1,O3,C2,I2,L2,G1,A1); forcing A and G adjacent (glued as one block) gives 1,663,2001{,}663{,}200 arrangements.

Arrangements of nn objects with repeats =n!p1! p2! ⋯=\dfrac{n!}{p_1!\,p_2!\,\cdots}. To force two specific letters adjacent, glue them into a single block (which can be ordered internally in 2!2! ways), then arrange all remaining units with the same repetition formula.

  1. List letters of SOCIOLOGICAL: S,O,C,I,O,L,O,G,I,C,A,L → n=12n=12, with O=3=3, C=2=2, I=2=2, L=2=2, S=1=1, G=1=1, A=1=1.
  2. Glue A and G into a single block [AG][AG], which internally can be AGAG or GAGA: 22 orders.
  3. Remaining letters after removing A and G: S,O,C,I,O,L,O,I,C,L → 10 letters with O=3=3, C=2=2, I=2=2, L=2=2, S=1=1.
  4. Total units to arrange =10=10 letters + 1+\,1 block =11=11 units.
  5. Arrange the 11 units (O,C,I,L repeated as counted, S and the block unique): …

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