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Exercise 6.1 · Q1

Q.Compute

(i) 6!6!
(ii) 8!6!×2!\dfrac{8!}{6! \times 2!}
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✓ Free question

Evaluate two factorial expressions: 6!6! directly, and 8!6!×2!\dfrac{8!}{6!\times2!} by cancelling the common 6!6! factor.

The factorial of a non-negative integer nn is

n!=n×(n−1)×(n−2)×⋯×2×1,0!=1n! = n\times(n-1)\times(n-2)\times\cdots\times2\times1,\qquad 0!=1

Key simplification trick: for m>nm>n, m!=m×(m−1)×⋯×(n+1)×n!m! = m\times(m-1)\times\cdots\times(n+1)\times n!, so a larger factorial can be written in terms of a smaller one and cancelled.

(i) Compute 6!6!

  1. 6!=6×5×4×3×2×16! = 6\times5\times4\times3\times2\times1.
  2. Multiply step by step: 6×5=306\times5=30, 30×4=12030\times4=120, 120×3=360120\times3=360, 360×2=720360\times2=720, 720×1=720720\times1=720.

(ii) Compute 8!6!×2!\dfrac{8!}{6!\times2!}

  1. Write 8!=8×7×6!8! = 8\times7\times6! (peeling off the top two factors so the common 6!6! can cancel with the denominator's 6!6!).
  2. 8!6!×2!=8×7×6!6!×2!=8×72!\dfrac{8!}{6!\times2!} = \dfrac{8\times7\times6!}{6!\times2!} = \dfrac{8\times7}{2!}.
  3. 2!=2×1=22! = 2\times1 = 2, and 8×7=568\times7=56.
  4. So the expression =562=28= \dfrac{56}{2} = 28.

Self-check (ii): Directly, 8!=403208!=40320, 6!=7206!=720, 2!=22!=2; 6!×2!=14406!\times2! = 1440; 40320/1440=2840320/1440 = 28. ✓ Matches the cancelled computation.

✓Final answer

(i) 6!=7206! = 720  

(ii) 8!6!×2!=28\dfrac{8!}{6!\times2!} = 28

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