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Worked Examples · Example 5

Q.If A×B={(a,x),(a,y),(b,x),(b,y)}A \times B = \{(a, x), (a, y), (b, x), (b, y)\}, then find AA and BB.

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Reading off the distinct first and second components of the given pairs gives A={a,b}A=\{a,b\} and B={x,y}B=\{x,y\}.

For A×B={(a,b):a∈A,b∈B}A\times B=\{(a,b):a\in A,b\in B\}, the set AA is exactly the collection of distinct first components appearing, and BB is exactly the collection of distinct second components appearing, provided every combination of these is present (which characterizes a genuine Cartesian product).

  1. Given.

A×B={(a,x),(a,y),(b,x),(b,y)}A\times B=\{(a,x),(a,y),(b,x),(b,y)\}

  1. Extract distinct first components (these form AA):

{a, a, b, b} ⇒ A={a,b}\{a,\ a,\ b,\ b\}\ \Rightarrow\ A=\{a,b\}

  1. Extract distinct second components (these form BB):

{x, y, x, y} ⇒ B={x,y}\{x,\ y,\ x,\ y\}\ \Rightarrow\ B=\{x,y\}

  1. Verify by reconstructing the Cartesian product. A×B={a,b}×{x,y}={(a,x),(a,y),(b,x),(b,y)}A\times B=\{a,b\}\times\{x,y\}=\{(a,x),(a,y),(b,x),(b,y)\} …

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