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Exercise 4.1 · Q1

Q.Determine whether each of the following relations are reflexive, symmetric and transitive.

(i) Relation RR in a set S={1,2,3,4,5}S = \{1, 2, 3, 4, 5\} as R={(x,y):y is divisible by x}R = \{(x, y) : y \text{ is divisible by } x\}
(ii) Relation RR in a set LL of all lines in a plane as R={(L1,L2):L1⊥L2}R = \{(L_1, L_2) : L_1 \perp L_2\}
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✓ Free question

Check each of the three properties directly against the definitions using elements of the given set.

RR is reflexive if (x,x)∈R ∀x(x,x)\in R\ \forall x; symmetric if (x,y)∈R⇒(y,x)∈R(x,y)\in R \Rightarrow (y,x)\in R; transitive if (x,y)∈R,(y,z)∈R⇒(x,z)∈R(x,y)\in R,(y,z)\in R \Rightarrow (x,z)\in R.

  1. (i) S={1,2,3,4,5}S=\{1,2,3,4,5\}, R={(x,y):y is divisible by x}R=\{(x,y): y \text{ is divisible by } x\}.
    • Reflexive: every xx divides itself, so (x,x)∈R ∀x∈S(x,x)\in R\ \forall x\in S. Reflexive.
    • Symmetric: take x=1,y=2x=1,y=2: 22 is divisible by 11, so (1,2)∈R(1,2)\in R. But is 11 divisible by 22? No. So (2,1)∉R(2,1)\notin R. Not symmetric.
    • Transitive: if yy is divisible by xx (i.e. y=kxy=kx) and zz is divisible by yy (i.e. z=myz=my), then z=m(kx)=(mk)xz=m(kx)=(mk)x, so zz is divisible by xx, i.e. (x,z)∈R(x,z)\in R. Transitive.
    • Conclusion: reflexive and transitive, not symmetric.
  2. (ii) L=L= all lines in a plane, R={(L1,L2):L1⊥L2}R=\{(L_1,L_2): L_1\perp L_2\}.
    • Reflexive: a line is never perpendicular to itself, so (L1,L1)∉R(L_1,L_1)\notin R. Not reflexive.
    • Symmetric: if L1⊥L2L_1\perp L_2 then automatically L2⊥L1L_2\perp L_1 (perpendicularity is a mutual relation). Symmetric.
    • Transitive: if L1⊥L2L_1\perp L_2 and L2⊥L3L_2\perp L_3, then L1L_1 is parallel to L3L_3 (not perpendicular). E.g. L1L_1 = x-axis, L2L_2 = y-axis, L3L_3 = x-axis again is degenerate, but take L3L_3 any line parallel to L1L_1: L1⊥L2L_1\perp L_2, L2⊥L3⇒L1∥L3L_2\perp L_3 \Rightarrow L_1\parallel L_3, so (L1,L3)∉R(L_1,L_3)\notin R. Not transitive.
    • Conclusion: symmetric only, neither reflexive nor transitive.
✓Final answer

  1. Reflexive + transitive, not symmetric.
  2. Symmetric only, not reflexive, not transitive.

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