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Worked Examples · Example 6

Q.Let A={1,2,3,{4},5}A = \{1, 2, 3, \{4\}, 5\}. Which of the following are incorrect? Give reasons.

(i) 1∈A1 \in A
(ii) {1,2}⊆A\{1, 2\} \subseteq A
(iii) {1,2,4}⊆A\{1, 2, 4\} \subseteq A
(iv) {4}∈A\{4\} \in A
(v) ϕ⊆A\phi \subseteq A
(vi) {4}⊆A\{4\} \subseteq A
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A={1,2,3,{4},5}A=\{1,2,3,\{4\},5\} has {4}\{4\} (a set) as one of its elements, NOT the number 44 itself — this distinction decides each statement.

"x∈Ax\in A" means xx is directly listed as an element of AA. "X⊆AX\subseteq A" means every element of the set XX is an element of AA. Note carefully: 4∉A4\notin A, but {4}∈A\{4\}\in A.

  1. (i) 1∈A1\in A. 11 is listed directly as an element of AA. Correct.
  2. (ii) {1,2}⊆A\{1,2\}\subseteq A. Both 1∈A1\in A and 2∈A2\in A. Correct.
  3. (iii) {1,2,4}⊆A\{1,2,4\}\subseteq A. Requires 1∈A1\in A ✓, 2∈A2\in A ✓, and 4∈A4\in A. But AA's elements are 1,2,3,{4},51,2,3,\{4\},5 — the number 44 is not among them (only the set {4}\{4\} is). So 4∉A4\notin A. Incorrect.
  4. (iv) {4}∈A\{4\}\in A. The set {4}\{4\} is literally listed as one of the five elements of AA. Correct. …

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