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NCERT Exemplar · Q5

Q.In PO4^3- ion the formal charge on the oxygen atom of P–O bond is

(i) + 1
(ii) – 1
(iii) – 0.75
(iv) + 0.75
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In the Lewis structure of PO43−\text{PO}_4^{3-}, the oxygen of a P–O single bond has V=6V=6, L=6L=6 (three lone pairs) and B=2B=2, giving a formal charge of 6−6−1=−16-6-1 = \boxed{-1} — option (ii).

Working through the structure

The phosphate ion has 5+4(6)+3=325 + 4(6) + 3 = 32 valence electrons. Its conventional Lewis structure places P at the centre with one P=O double bond and three P–O single bonds; each singly-bonded oxygen completes its octet with three lone pairs and carries the ion's negative charges.

For a singly-bonded O: V=6V = 6, lone-pair electrons L=6L = 6, bonding electrons B=2B = 2:

F.C.=6−6−12(2)=−1\text{F.C.} = 6 - 6 - \tfrac{1}{2}(2) = -1 …

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