Q.Find the sum of the following series up to terms:
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Start your 14-day free trial to unlock the full solution →Both series are built from repeating digits. The key is to rewrite each term as a multiple of a geometric series: and . Summing the geometric parts gives closed forms: (i) and (ii) .
Why this approach works
When you see a series like , the pattern is obvious — each term appends another digit 5. But adding these directly is messy. The insight is to notice that , , and so on. And (with ones) is exactly . That turns the problem into a sum of powers of 10, which is a geometric series — something we know how to handle cleanly.
The second series is the same idea, just shifted to the right of the decimal point. (with sixes) equals . Again, the sum becomes a geometric series in .
(i) up to terms
Step 1: Write each term using the "repunit" trick
A number with digits all equal to 5 can be written as:
So the -th term of the series is:
Step 2: Sum from to
Let be the sum of the first terms:
Separate the sum:
Step 3: Evaluate each part
The first sum is a geometric series with first term , common ratio :
The second sum is just ones:
Step 4: Combine
Put over a common denominator :
Simplify:
A quick check: for , . Plug into the formula: . Works.
(ii) up to terms
Step 1: Rewrite each term
A decimal like with sixes after the decimal point is:
Why? Because , and with sixes is minus the tail that starts after the -th place. That tail is .
So the -th term is:
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