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NCERT Exemplar · Q9

Q.A proton has spin and magnetic moment just like an electron. Why then its effect is neglected in magnetism of materials?

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A spin magnetic moment scales as μ∝1/m\mu \propto 1/m; the proton is ∼1836×\sim1836\times heavier than the electron, so μp≈μB/660\mu_p \approx \mu_B/660 — about 660660 times smaller. Bulk magnetism is governed by electron moments, so the proton's contribution is negligible.

Why a spin moment depends on mass

Both particles have spin 12\tfrac12, so each has an intrinsic magnetic moment. For a particle of charge qq, mass mm and gyromagnetic factor gg,

μ=g q2m S,S=ℏ2.\mu = g\,\frac{q}{2m}\,S, \qquad S = \frac{\hbar}{2}.

The two particles carry the same magnitude of charge, so the moment is controlled by the charge-to-mass ratio q/mq/m — and hence by the mass.

Comparing proton and electron

The natural units are the Bohr and nuclear magnetons:

μB=eℏ2me,μN=eℏ2mp,μNμB=memp≈11836.\mu_B = \frac{e\hbar}{2m_e}, \qquad \mu_N = \frac{e\hbar}{2m_p}, \qquad \frac{\mu_N}{\mu_B} = \frac{m_e}{m_p} \approx \frac{1}{1836}.

The measured moments are μe≈μB\mu_e \approx \mu_B (electron g≈2g\approx2) and μp≈2.79 μN\mu_p \approx 2.79\,\mu_N (proton g≈5.6g\approx5.6, from its composite structure). Therefore

μp≈2.79 μN=2.791836 μB≈μB660.\mu_p \approx 2.79\,\mu_N = \frac{2.79}{1836}\,\mu_B \approx \frac{\mu_B}{660}.

So even with the larger gg-factor, the proton's moment is about 660660 times smaller than the electron's.

Watch out

Equal spin quantum number does not mean equal magnetic moment. The moment depends on q/mq/m, and the proton's much larger mass crushes it.

Why it is negligible in materials …

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