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Q.In a knock-out tournament of 19 teams, the total number of matches played is:

(a) 18
(b) 19
(c) 20
(d) 32
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In a knockout tournament with 19 teams, the total number of matches played is 18.

Understanding Knockout Tournament Matches

A knockout (or elimination) tournament is structured so that every match eliminates exactly one team. The winner advances, the loser is out. This simple principle leads directly to a beautiful result: if you start with N teams and need to crown one champion, you must eliminate exactly N - 1 teams. Since each match eliminates precisely one team, the total number of matches is always N - 1.

This holds regardless of how the bracket is arranged, how many byes are given, or how many rounds the tournament runs. The logic is ironclad: 19 teams enter, 1 champion emerges, so 18 teams must be eliminated, requiring 18 matches.

Total number of matches = N - 1

where N is the number of teams.

Applying the Formula

For this question, N = 19 teams.

Total matches = 19 - 1 = 18

The tournament will proceed through multiple rounds. Since 19 is not a power of 2, some teams will receive byes in the first round. The next higher power of 2 is 32, so the number of byes is 32 - 19 = 13. This means 13 teams skip the first round, and 19 - 13 = 6 teams play in the first round, producing 3 matches. After the first round, 13 + 3 = 16 teams remain (a power of 2), and the bracket proceeds cleanly: 8 matches in the second round, 4 in the third, 2 in the semi-finals, and 1 final. Summing these: 3 + 8 + 4 + 2 + 1 = 18 matches.

Note

The number of byes and the structure of rounds may vary, but the total match count is always determined by N - 1. This formula is a direct consequence of the elimination principle. …

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