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Q.Using amperes circuital law in magnetism, derive an expression for the intensity of magnetic field due to a straight current carrying wire.

Goa GbshseGBSHSE Class 12 Board Exam 2025Subjective· 2mImportance★★★★★
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Applying Ampere's circuital law to a circular Amperian loop centred on the wire, and using the symmetry that BB is constant in magnitude and tangential everywhere on that loop, gives B=μ0I/2πrB=\mu_0 I/2\pi r.

Consider an infinitely long straight wire carrying a steady current II. By symmetry, the magnetic field lines around the wire are concentric circles centred on the wire, and the field magnitude BB is the same at every point on a circle of a given radius rr (and everywhere tangential to it).

Choose a circular Amperian loop of radius rr, centred on the wire and lying in a plane perpendicular to it. Ampere's circuital law states

∮B⃗⋅dl⃗=μ0Ienc\oint \vec B \cdot d\vec l = \mu_0 I_{enc}

Since B⃗\vec B is tangential to the loop everywhere and constant in magnitude, B⃗⋅dl⃗=B dl\vec B\cdot d\vec l = B\,dl, so

∮B dl=B∮dl=B(2πr)\oint B\,dl = B\oint dl = B(2\pi r)

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