Q.age = int(input("Enter your age "))
if age >= 18: # use ':' to indicate end of condition.
print("Eligible to vote")

This is a Plain theory question — it asks about the concept of string input type in Python, specifically how input() works and what type it returns.

When you call input() in Python, it always returns a string, regardless of what the user types. Even if the user enters a number like 25, the value stored is the string "25", not the integer 25.

In the code shown:

age = int(input("Enter your age "))

The input() function first reads the user's keystrokes as a string. That string is then passed to int(), which converts it to an integer. If the user types something that cannot be converted — like "eighteen" — Python raises a ValueError at runtime.

The key point: input() alone gives a string. To get a numeric type, you must explicitly wrap it with int(), float(), or another type constructor. …

This is a code-analysis / debugging question. The code looks correct at first glance, but it contains a subtle type mismatch that will crash the program at runtime.

The Core Idea: input() Returns a String

The input() function in Python reads whatever the user types as a string — always. Even if the user types a number like 20, Python stores it as the string "20". This is a deliberate design choice: it gives the programmer full control over type conversion.

So when the user runs this code and enters 20, the variable age holds "20" (a string), not 20 (an integer).

What Happens Next

The if condition checks age >= 18. Python tries to compare a string ("20") with an integer (18). In Python 3, comparing a string with an integer raises a TypeError — the program crashes before it can print anything.

Step-by-Step Trace

The program never reaches the print() statement.

Why the Other Options Would Be Wrong (if this were an MCQ) …