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Q.Mark the correct order of decreasing acid strength of the following compounds.

(a) Phenol
(b) 4-Nitrophenol (NO2 para to OH)
(c) 3-Methoxyphenol (OCH3 meta to OH)
(d) 3-Nitrophenol (NO2 meta to OH)
(e) 4-Methoxyphenol (OCH3 para to OH)
(a)
(e) >
(d) >
(b) >
(a) >
(c)
(b)
(b) >
(d) >
(a) >
(c) >
(e)
(c)
(d) >
(e) >
(c) >
(b) >
(a)
(d)
(e) >
(d) >
(c) >
(b) > (a)
Gujarat GsebGSEB Higher Secondary Certificate (HSC) Examination 2026MCQ· 1mImportance★★★★★
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Acidity of a substituted phenol rises with electron-withdrawing substituents (which stabilise the phenoxide anion) and falls with electron-donating substituents (which destabilise it), with the effect strongest when the group is para/ortho (conjugated) to –OH.

When phenol loses H+ to form the phenoxide ion, the negative charge is delocalised onto the ring, especially onto the ortho and para carbons. A substituent's effect on acidity depends on how it interacts with that delocalised negative charge:

  • –NO2 (strongly electron-withdrawing) pulls electron density away, stabilising the anion and INCREASING acidity — most strongly when placed para/ortho (direct resonance with the developing negative charge), and to a smaller extent even at meta (inductive-only). So both nitrophenols are more acidic than plain phenol, with the para-nitrophenol (b) the strongest acid (full resonance stabilisation) ahead of meta-nitrophenol (d, inductive only). …

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