Q.Which one of the following compounds is more reactive towards SN2 reaction and why ?
CH3CH(Cl)CH2CH3 or CH3CH2CH2Cl
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🔒 Start your 14-day free trial to unlock the full solution →Concept understanding — SN1 and SN2 Mechanism
The Core Idea: Two Ways to Swap a Group
Imagine you have a molecule with a leaving group (like a halogen) attached to a carbon. You want to replace that leaving group with a nucleophile (something that loves positive charge). There are two fundamentally different ways this can happen — like two different ways to replace a lightbulb.
SN2 is like unscrewing the old bulb and screwing in the new one in one smooth motion. SN1 is like first pulling the old bulb out completely, leaving an empty socket, and then putting the new bulb in.
That empty socket — the carbocation — is the key difference.
SN2: One Step, Backside Attack
The name says it all: Substitution, Nucleophilic, Bimolecular. "Bimolecular" means two molecules (the nucleophile and the substrate) are involved in the rate-determining step.
The Mechanism
The nucleophile attacks the carbon from the backside — directly opposite the leaving group. As the nucleophile approaches, the leaving group starts to leave. At the transition state, the nucleophile is partially bonded and the leaving group is partially detached. Then the leaving group departs completely, and the nucleophile is fully bonded.
All of this happens in one step — no intermediate.
The Stereochemistry: Inversion
Because the nucleophile attacks from the back, the configuration at the carbon inverts — like an umbrella turning inside out in a strong wind. If you start with an R configuration, you get S (and vice versa). This is called Walden inversion.
What Favours SN2?
- Primary carbon (least steric hindrance — the backside is wide open)
- Strong nucleophile (needs to push its way in)
- Good leaving group (but not too good — it needs to wait for the nucleophile)
- Polar aprotic solvent (doesn't solvate the nucleophile too tightly)
SN2 is impossible on tertiary carbons — the three bulky groups block the backside completely. The nucleophile simply cannot get close enough.
SN1: Two Steps, Carbocation Intermediate
Substitution, Nucleophilic, Unimolecular. "Unimolecular" means only one molecule (the substrate) is involved in the rate-determining step.
The Mechanism
Step 1 (slow, rate-determining): The leaving group leaves on its own, forming a carbocation (a carbon with only six electrons — positively charged and very unstable).
Step 2 (fast): The nucleophile attacks the carbocation. Since the carbocation is flat (trigonal planar), the nucleophile can attack from either side with equal probability.
The Stereochemistry: Racemisation
Because the nucleophile can attack from either face of the flat carbocation, you get a racemic mixture — equal amounts of R and S. If the starting material is optically pure, the product will be optically inactive.
In practice, you often get slightly more inversion than retention (about 60:40) because the leaving group can partially block one face as it departs. But the key idea is loss of stereochemistry.
What Favours SN1?
- Tertiary carbon (the carbocation is stabilised by three alkyl groups — hyperconjugation and inductive effect)
- Weak nucleophile (doesn't need to force its way in — the carbocation is desperate for electrons)
- Excellent leaving group (must be able to leave on its own)
- Polar protic solvent (stabilises the carbocation and the leaving group)
SN1 is impossible on primary carbons — a primary carbocation is so unstable it effectively doesn't exist. The leaving group would never leave on its own.
The Big Comparison Table …
SN2 rate is governed by steric crowding at the carbon bearing the halogen: a primary (less hindered) carbon reacts faster than a secondary one. …
CH3CH2CH2Cl (primary) beats CH3CH(Cl)CH2CH3 (secondary) in SN2 because a primary carbon has less steric hindrance to backside nucleophilic attack.
Concept. The SN2 mechanism (CBSE Class-12 haloalkanes-and-haloarenes) is a one-step, concerted attack of the nucleophile from the side opposite the leaving group.
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- GSEB Higher Secondary Certificate (HSC) Examination 2025Set ANNUAL1 markMCQQ.For the following compounds, what is the correct increasing order of reactivity towards SN2 displacement. (I) 2-Bromo 2-Methyl butane (II) 1-Bromo Pentane (III) 2-Bromo Pentane(a) II < III < I(b) II < I < III(c) I < III < II(d) I < II < III
›Reveal solutionSolution
SN2 reactivity decreases as steric bulk around the carbon bearing the leaving group increases: primary > secondary > tertiary.
SN2 is a bimolecular, single-step mechanism where the nucleophile attacks the electrophilic carbon from the backside, opposite to the leaving group. This transition state is very sensitive to steric crowding around that carbon.
(I) 2-Bromo-2-methylbutane - the C-Br carbon is tertiary (three alkyl groups attached) - most hindered, LEAST reactive towards SN2.
(III) 2-Bromopentane - the C-Br carbon is secondary - moderately hindered. …
- GSEB Higher Secondary Certificate (HSC) Examination 2023Set ANNUAL1 markMCQQ.Which compound has highest reactivity towards SN2 reaction?(a) 1-Bromo-3-methylbutane(b) 1-Bromo-2-methylbutane(c) 1-Bromobutane(d) 1-Bromo-2,2-dimethylpropane
›Reveal solutionSolution
SN2 rate falls with steric crowding; 1-bromobutane (unbranched primary) reacts fastest.
SN2 proceeds through a crowded transition state, so less steric hindrance around the carbon bearing the halogen means faster reaction.
- 1-Bromobutane: straight-chain primary, no branch near C-Br -> least hindered -> fastest SN2.
- 1-Bromo-2-methylbutane: branch at the beta carbon -> more hindered. …
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