Q.Let the relation R be defined on the set A={1,2,3,4,5} by R={(a,b):∣a2−b2∣<8}. Then R is given by ______.
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Properties of a Relation
A relation R on a set A pairs elements of A with one another. Some relations behave in regular, predictable ways, and we name these behaviours properties. Three matter most for CBSE Class 12 — reflexive, symmetric, transitive (together they build an equivalence relation); a fourth, antisymmetric, is worth knowing for order relations.
Reflexive — everything relates to itself
R is reflexive if aRa for every a∈A. "Has the same age as" is reflexive; "is taller than" is not. If even one element misses its self-pair, reflexivity fails: on {1,2,3}, {(1,1),(2,2)} is not reflexive because (3,3) is absent.
Symmetric — the relation runs both ways
R is symmetric if aRb⟹bRa. "Is married to" is symmetric; "is taller than" is not. Symmetry does not demand that every pair be related — only that any pair which appears also appears reversed. So {(1,2),(2,1),(3,3)} is symmetric, but {(1,2),(2,1),(1,3)} is not, since (3,1) is missing.
Transitive — relations chain
R is transitive if aRb and bRc together force aRc. "Is an ancestor of" is transitive; "is a friend of" is not. A single broken chain breaks the property: {(1,2),(2,3)} is not transitive because (1,3) is missing.
Antisymmetric — two-way ties force equality
R is antisymmetric if aRb and bRa together force a=b. The order relation ≤ is antisymmetric: a≤b and b≤a give a=b. It does not ban self-pairs like (1,1); it only rules out distinct elements related both ways.
Test the properties in order of ease — reflexivity first, then symmetry, transitivity. A single counterexample is enough to disprove any of them.
| Property | Condition |
|---|---|
| Reflexive | ∀a, aRa |
Concept: Relation Properties — we first list all ordered pairs that satisfy the condition, then check which pairs are present.
Step 1: For each a,b∈A, compute ∣a2−b2∣ and check if it is <8.
Step 2:
- 12=1, 22=4, 32=9, 42=16, 52=25. Differences less than 8 occur only between numbers whose squares differ by at most 7.
Step 3: List all pairs:
- With a=1: ∣1−1∣=0, ∣1−4∣=3, ∣1−9∣=8 (not included) → (1,1),(1,2) and symmetrically (2,1).
- With a=2: ∣4−1∣=3, ∣4−4∣=0, ∣4−9∣=5, ∣4−16∣=12 → (2,1),(2,2),(2,3) and (3,2).
- With a=3: ∣9−4∣=5, ∣9−9∣=0, ∣9−16∣=7, ∣9−25∣=16 → (3,2),(3,3),(3,4) and (4,3). …
Listing every ordered pair of A={1,2,3,4,5} with ∣a2−b2∣<8 gives an 11-element relation.
We need all ordered pairs (a,b) with a,b∈{1,2,3,4,5} satisfying ∣a2−b2∣<8. The squares are 1,4,9,16,25.
- Every pair with a=b gives ∣a2−b2∣=0<8: (1,1),(2,2),(3,3),(4,4),(5,5).
- (1,2) and (2,1): ∣1−4∣=3<8 ✓
- (2,3) and (3,2): ∣4−9∣=5<8 ✓
- (3,4) and (4,3): ∣9−16∣=7<8 ✓ …
Method: Building a Relation in Roster Form From a Condition
Use this when a relation on a small finite set is defined by a condition such as ∣a2−b2∣<8 and you must list its pairs.
Steps
Step 1: Precompute the key quantity for each element.
Here, list the squares a2 for every a in the set so comparisons are quick.
Step 2: Test each ordered pair against the condition. …
Common Mistakes
Mistake 1: Including a pair that meets the boundary exactly.
Why it's wrong: the condition is ∣a2−b2∣<8 (strict), so a pair like (1,3) with ∣1−9∣=8 does not qualify. Correct approach: admit only differences strictly less than 8.
Mistake 2: Listing (a,b) but forgetting (b,a). …
- GUJCET 2026Set x1 markMCQQ.Let R be the relation in the set N given by R={(a,b):a=b−2, b<6}, then ______ (A) (6,8)∈R (B) (8,7)∈R (C) (8,3)∈R (D) (2,4)∈R
›Reveal solutionSolution
Test each pair against both conditions a=b−2 and b<6.
- (6,8): b=8<6. ✗
- (8,7): b=7<6. ✗
- (8,3): a=b−2=1=8. ✗ …
- GSEB Higher Secondary Certificate (HSC) Examination 2025Set ANNUAL1 markMCQQ.A relation R on the set N is defined by R={(a,b)∣a=b−2, b>6}.(a) (2,4)∈R(b) (6,8)∈R(c) (3,8)∈R(d) (8,7)∈R
›Reveal solutionSolution
Test each pair against both conditions: a=b−2 and b>6.
- (2,4): 2=4−2 holds, but 4>6 fails.
- (6,8): 6=8−2 holds, and 8>6 holds -- both conditions satisfied. …
- GSEB Higher Secondary Certificate (HSC) Examination 2024Set ANNUAL1 markMCQQ.The relation R={(a,b),(b,a)} is defined on the set {a,b,c}, then R is ______.(a) Reflexive, but not symmetric and transitive(b) Symmetric, but not reflexive and transitive(c) Transitive, but not reflexive and symmetric(d) An equivalence relation
›Reveal solutionSolution
Check each property of R={(a,b),(b,a)} on {a,b,c} directly against its definition.
Reflexive? Needs (a,a),(b,b),(c,c)∈R -- none are present, so R is NOT reflexive.
Symmetric? (a,b)∈R⇒(b,a)∈R -- both pairs are present, so R IS symmetric.
…
- GSEB Higher Secondary Certificate (HSC) Examination 2022Set ANNUAL1 markMCQQ.Let R be the relation in the set {1,2,3} given by R={(1,1),(2,2),(3,3)}. Choose the correct answer.(a) R is an equivalence relation(b) R is reflexive and symmetric but not transitive(c) R is reflexive and transitive but not symmetric(d) R is symmetric and transitive but not reflexive
›Reveal solutionSolution
Check the three properties on R={(1,1),(2,2),(3,3)}.
Reflexive: (1,1),(2,2),(3,3) are all present ✓.
Symmetric: every pair is of the form (a,a), so (a,a)⇒(a,a) ✓. …
- GSEB Higher Secondary Certificate (HSC) Examination 2022Set ANNUAL1 markMCQQ.Consider a binary operation ∗ on N defined as a∗b=∣a−b∣. Choose the correct answer.(a) ∗ is both associative and commutative(b) ∗ is commutative but not associative(c) ∗ is associative but not commutative(d) ∗ is neither commutative nor associative
›Reveal solutionSolution
Test commutativity and associativity of a∗b=∣a−b∣.
Commutative: a∗b=∣a−b∣=∣b−a∣=b∗a ✓.
Associative? (a∗b)∗c=∣a−b∣−c, while a∗(b∗c)=a−∣b−c∣. …
- GSEB Higher Secondary Certificate (HSC) Examination 2020Set ANNUAL1 markMCQQ.Let R be the relation on the set N given by R={(a,b):a=b−2, b>6}. Choose the correct answer.(a) (2,4)∈R(b) (3,8)∈R(c) (6,8)∈R(d) (8,7)∈R
›Reveal solutionSolution
Check each ordered pair against both conditions of the relation: a=b−2 AND b>6.
R={(a,b):a=b−2, b>6} on N.
- (2,4): a=b−2⇒2=4−2 ✓, but b>6⇒4>6 ✗. Rejected.
- (3,8): a=b−2⇒3=8−2=6? ✗. Rejected. …
- GSEB Higher Secondary Certificate (HSC) Examination 2019Set ANNUAL1 markMCQQ.The relation S={(1,1),(2,2),(3,3),(4,4),(5,5)} on {1,2,3,4,5} is ______.(a) reflexive only(b) symmetric only(c) transistive only(d) an equivalence relation
›Reveal solutionSolution
S={(a,a):a∈{1,...,5}} is the identity relation, and the identity relation is always an equivalence relation.
…
- GSEB Higher Secondary Certificate (HSC) Examination 2018Set ANNUAL1 markMCQQ.If a∗b=a3+b3 on z, then (1∗2)∗0= ___.(a) 0(b) 729(c) 81(d) 27
›Reveal solutionSolution
Evaluate the operation from the inside out.
Given a∗b=a3+b3 on Z.
First 1∗2=13+23=1+8=9.
…
- GSEB Higher Secondary Certificate (HSC) Examination 2018Set ANNUAL1 markMCQQ.If the relation is defined on R−{0} by (x,y)∈S⇔xy>0, then S is ___.(a) an equivalence relation(b) symmetric only(c) reflexive only(d) transitive only
›Reveal solutionSolution
"Same sign" is reflexive, symmetric and transitive on R−{0}.
- Reflexive: x⋅x=x2>0 for xe0, so (x,x)∈S.
- Symmetric: xy>0⇒yx>0. …
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