Q.Check whether the relation R in R defined by R={(a,b):a≤b3} is reflexive, symmetric or transitive.
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🔒 Start your 14-day free trial to unlock the full solution →Concept understanding — Relation Properties
Properties of a Relation
A relation R on a set A pairs elements of A with one another. Some relations behave in regular, predictable ways, and we name these behaviours properties. Three matter most for CBSE Class 12 — reflexive, symmetric, transitive (together they build an equivalence relation); a fourth, antisymmetric, is worth knowing for order relations.
Reflexive — everything relates to itself
R is reflexive if aRa for every a∈A. "Has the same age as" is reflexive; "is taller than" is not. If even one element misses its self-pair, reflexivity fails: on {1,2,3}, {(1,1),(2,2)} is not reflexive because (3,3) is absent.
Symmetric — the relation runs both ways
R is symmetric if aRb⟹bRa. "Is married to" is symmetric; "is taller than" is not. Symmetry does not demand that every pair be related — only that any pair which appears also appears reversed. So {(1,2),(2,1),(3,3)} is symmetric, but {(1,2),(2,1),(1,3)} is not, since (3,1) is missing.
Transitive — relations chain
R is transitive if aRb and bRc together force aRc. "Is an ancestor of" is transitive; "is a friend of" is not. A single broken chain breaks the property: {(1,2),(2,3)} is not transitive because (1,3) is missing.
Antisymmetric — two-way ties force equality
R is antisymmetric if aRb and bRa together force a=b. The order relation ≤ is antisymmetric: a≤b and b≤a give a=b. It does not ban self-pairs like (1,1); it only rules out distinct elements related both ways.
Test the properties in order of ease — reflexivity first, then symmetry, transitivity. A single counterexample is enough to disprove any of them.
| Property | Condition |
|---|---|
| Reflexive | ∀a, aRa |
The key idea is to test each property individually — reflexivity, symmetry, transitivity — using the definition a≤b3.
-
Reflexive: For any a∈R, we need a≤a3. This fails for a=21, since 21≤81 is false. So R is not reflexive.
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Symmetric: If a≤b3, does b≤a3 follow? Take a=1, b=2: 1≤8 holds, but 2≤1 is false. So R is not symmetric. …
The relation R={(a,b):a≤b3} on R is neither reflexive, nor symmetric, nor transitive.
We test each property directly against the defining rule a≤b3. A single counterexample is enough to disprove a property.
1. Reflexivity
Reflexivity would require a≤a3 for every real number a.
Take a=21:
21≤(21)3=81?
This is false, since 21>81. So (21,21)∈/R.
R is not reflexive.
For 0<a<1 the cube is smaller than the number itself, so a≤a3 fails. Cubes only "grow" for a>1.
2. Symmetry
Symmetry would require: whenever a≤b3, also b≤a3.
Take a=1, b=2:
a≤b3:1≤23=8✓so (1,2)∈R.
But
b≤a3:2≤13=1×so (2,1)∈/R.
R is not symmetric.
3. Transitivity …
Method: Testing an Inequality Relation with a Cube
Use this for relations like aRb⟺a≤b3. The cube on one side is exactly what makes each property fail, so aim your test cases at that asymmetry.
Steps
Step 1: Reflexive — check a≤a3 across the domain
Try values in (0,1) where a cube shrinks the number: a=21 gives 21≤81, false, so it is not reflexive.
Step 2: Symmetric — swap a mismatched pair
Pick a small and b larger: (1,2) has 1≤8 true, but (2,1) needs 2≤1, false.
Step 3: Transitive — chain toward a broken bound …
Common Mistakes
Mistake 1: Testing reflexivity only with numbers >1
Why it's wrong: a≤a3 holds for a≥1 but fails for 0<a<1, where the cube is smaller. Correct approach: include fractional test values.
Mistake 2: Assuming a cube relation behaves symmetrically
Why it's wrong: cubing one side breaks the balance, so 1≤23 does not imply 2≤13. Correct approach: test the reverse pair explicitly. …
- GUJCET 2026Set x1 markMCQQ.Let R be the relation in the set N given by R={(a,b):a=b−2, b<6}, then ______ (A) (6,8)∈R (B) (8,7)∈R (C) (8,3)∈R (D) (2,4)∈R
›Reveal solutionSolution
Test each pair against both conditions a=b−2 and b<6.
- (6,8): b=8<6. ✗
- (8,7): b=7<6. ✗
- (8,3): a=b−2=1=8. ✗ …
- GSEB Higher Secondary Certificate (HSC) Examination 2025Set ANNUAL1 markMCQQ.A relation R on the set N is defined by R={(a,b)∣a=b−2, b>6}.(a) (2,4)∈R(b) (6,8)∈R(c) (3,8)∈R(d) (8,7)∈R
›Reveal solutionSolution
Test each pair against both conditions: a=b−2 and b>6.
- (2,4): 2=4−2 holds, but 4>6 fails.
- (6,8): 6=8−2 holds, and 8>6 holds -- both conditions satisfied. …
- GSEB Higher Secondary Certificate (HSC) Examination 2024Set ANNUAL1 markMCQQ.The relation R={(a,b),(b,a)} is defined on the set {a,b,c}, then R is ______.(a) Reflexive, but not symmetric and transitive(b) Symmetric, but not reflexive and transitive(c) Transitive, but not reflexive and symmetric(d) An equivalence relation
›Reveal solutionSolution
Check each property of R={(a,b),(b,a)} on {a,b,c} directly against its definition.
Reflexive? Needs (a,a),(b,b),(c,c)∈R -- none are present, so R is NOT reflexive.
Symmetric? (a,b)∈R⇒(b,a)∈R -- both pairs are present, so R IS symmetric.
…
- GSEB Higher Secondary Certificate (HSC) Examination 2022Set ANNUAL1 markMCQQ.Let R be the relation in the set {1,2,3} given by R={(1,1),(2,2),(3,3)}. Choose the correct answer.(a) R is an equivalence relation(b) R is reflexive and symmetric but not transitive(c) R is reflexive and transitive but not symmetric(d) R is symmetric and transitive but not reflexive
›Reveal solutionSolution
Check the three properties on R={(1,1),(2,2),(3,3)}.
Reflexive: (1,1),(2,2),(3,3) are all present ✓.
Symmetric: every pair is of the form (a,a), so (a,a)⇒(a,a) ✓. …
- GSEB Higher Secondary Certificate (HSC) Examination 2022Set ANNUAL1 markMCQQ.Consider a binary operation ∗ on N defined as a∗b=∣a−b∣. Choose the correct answer.(a) ∗ is both associative and commutative(b) ∗ is commutative but not associative(c) ∗ is associative but not commutative(d) ∗ is neither commutative nor associative
›Reveal solutionSolution
Test commutativity and associativity of a∗b=∣a−b∣.
Commutative: a∗b=∣a−b∣=∣b−a∣=b∗a ✓.
Associative? (a∗b)∗c=∣a−b∣−c, while a∗(b∗c)=a−∣b−c∣. …
- GSEB Higher Secondary Certificate (HSC) Examination 2020Set ANNUAL1 markMCQQ.Let R be the relation on the set N given by R={(a,b):a=b−2, b>6}. Choose the correct answer.(a) (2,4)∈R(b) (3,8)∈R(c) (6,8)∈R(d) (8,7)∈R
›Reveal solutionSolution
Check each ordered pair against both conditions of the relation: a=b−2 AND b>6.
R={(a,b):a=b−2, b>6} on N.
- (2,4): a=b−2⇒2=4−2 ✓, but b>6⇒4>6 ✗. Rejected.
- (3,8): a=b−2⇒3=8−2=6? ✗. Rejected. …
- GSEB Higher Secondary Certificate (HSC) Examination 2019Set ANNUAL1 markMCQQ.The relation S={(1,1),(2,2),(3,3),(4,4),(5,5)} on {1,2,3,4,5} is ______.(a) reflexive only(b) symmetric only(c) transistive only(d) an equivalence relation
›Reveal solutionSolution
S={(a,a):a∈{1,...,5}} is the identity relation, and the identity relation is always an equivalence relation.
…
- GSEB Higher Secondary Certificate (HSC) Examination 2018Set ANNUAL1 markMCQQ.If a∗b=a3+b3 on z, then (1∗2)∗0= ___.(a) 0(b) 729(c) 81(d) 27
›Reveal solutionSolution
Evaluate the operation from the inside out.
Given a∗b=a3+b3 on Z.
First 1∗2=13+23=1+8=9.
…
- GSEB Higher Secondary Certificate (HSC) Examination 2018Set ANNUAL1 markMCQQ.If the relation is defined on R−{0} by (x,y)∈S⇔xy>0, then S is ___.(a) an equivalence relation(b) symmetric only(c) reflexive only(d) transitive only
›Reveal solutionSolution
"Same sign" is reflexive, symmetric and transitive on R−{0}.
- Reflexive: x⋅x=x2>0 for xe0, so (x,x)∈S.
- Symmetric: xy>0⇒yx>0. …
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