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Q.The half life of (238,92)U undergoing alpha-decay is 4.5 x 10^9 years. What is the activity of 1 g of sample of (238,92)U?

Gujarat GsebGSEB Higher Secondary Certificate (HSC) Examination 2023Subjective· 2mImportance★★★★★
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Find the number of nuclei in 1 g (2.53x10^21), the decay constant lambda = 0.693/T_half (4.87x10^-18 s^-1), then activity A = lambda N = 1.23 x 10^4 Bq.

Number of nuclei in 1 g of U-238:

N = (mass/molar mass) x N_A = (1/238) x 6.022 x 10^23 = 2.53 x 10^21 nuclei.

Decay constant: lambda = 0.693/T_half. T_half = 4.5 x 10^9 years = 4.5 x 10^9 x 3.16 x 10^7 s = 1.42 x 10^17 s. …

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