Q.Justify giving reactions that among halogens, fluorine is the best oxidant and among hydrohalic compounds, hydroiodic (HI) acid is the best reductant.

What Makes a Halogen a Halogen?

Imagine you are a fluorine atom. You have seven electrons in your outermost shell. You are one electron short of a full, stable octet — that perfect, noble-gas configuration that every atom craves. That single missing electron makes you intensely hungry. You will grab an electron from almost anything that moves.

That hunger is the entire story of the halogens.

The Intuition: The One-Electron Gap

All elements in Group 17 — fluorine, chlorine, bromine, iodine, and astatine — share the same electronic signature: their outermost shell has seven electrons. The nearest noble gas has eight. So each halogen is exactly one electron short of stability.

This is not a small difference. It is the most powerful chemical drive in the periodic table. It means:

• Halogens are the most reactive non-metals in their respective periods.
• They exist naturally as diatomic molecules ($\text{F}_2$, $\text{Cl}_2$, $\text{Br}_2$, $\text{I}_2$) because two halogen atoms can share one electron each, giving both a pseudo-octet.
• When they react with metals, they gain one electron to become halide ions ($\text{F}^-$, $\text{Cl}^-$, $\text{Br}^-$, $\text{I}^-$), achieving the noble-gas configuration. The resulting compounds are called salts — sodium chloride, potassium iodide, calcium fluoride.

The Precise Statement

Group 17 elements (fluorine, chlorine, bromine, iodine, astatine) are highly reactive non-metals with the general electronic configuration $ns^2 np^5$ in their valence shell. Their characteristic oxidation state is −1, achieved by gaining one electron to form a halide ion. In their elemental form, they exist as diatomic molecules ($\text{X}_2$). Their reactivity decreases down the group: fluorine is the most reactive, iodine the least.

The Trend Down the Group

Why −1 and Not +1 or +7?

You might ask: if halogens have seven valence electrons, could they not lose seven electrons and show a +7 oxidation state? In principle, yes — chlorine, bromine, and iodine do show positive oxidation states (+1, +3, +5, +7) when bonded to more electronegative elements like oxygen. But the characteristic oxidation state, the one that defines their salt-forming behaviour, is −1.

The reason is simple: gaining one electron is energetically far cheaper than losing seven. The energy required to remove seven electrons is enormous; the energy released when one electron is added is substantial. So whenever a halogen meets a metal, the metal loses electrons and the halogen gains one. That is the fundamental exchange. …