Q.Consider the statements given below and then choose the correct output from the given options:

D={'S01':95, 'S02':96 }  
for I in D:  
    print(I,end='#')  

(A) S01#S02# (B) 95#96# (C) S01,95#S02,96# (D) S01#95#S02#96#

The key idea is dictionary iteration in Python. When a for loop iterates directly over a dictionary, it iterates through the dictionary's keys by default.

1. The dictionary D is {'S01': 95, 'S02': 96}.
2. The loop for I in D: iterates through the keys of D.
3. First iteration: I is 'S01', so print(I, end='#') outputs S01#.
4. Second iteration: I is 'S02', so it outputs S02#. …

A Python dictionary stores data as key-value pairs. Understanding how to iterate over these structures is fundamental. When you use a for loop directly on a dictionary, Python has a specific default behavior: it iterates over the keys of the dictionary. The loop variable will sequentially take on each key.

Additionally, the print() function in Python, by default, adds a newline character (\n) after whatever it prints. However, you can modify this behavior using the end parameter. If you set end='#', then instead of a newline, a hash symbol (#) will be appended after each item printed.

Let's break down the execution step-by-step.

1. Dictionary Initialization:

   The code begins by defining a dictionary D:

   D = {'S01':95, 'S02':96}

   This dictionary contains two key-value pairs:

   • The key 'S01' is associated with the value 95.
   • The key 'S02' is associated with the value 96.

2. Looping through the Dictionary:

   Next, a for loop is initiated: for I in D:.

   As discussed, when you iterate directly over a dictionary D, the loop variable I will take on the keys of the dictionary, one by one.

3. First Iteration:

   In the first pass of the loop, I is assigned the first key from D, which is 'S01'.

   The statement inside the loop is print(I, end='#').

   This command prints the current value of I (which is 'S01') and then appends the character specified by end, which is '#'.

   The output generated at this point is S01#.

4. Second Iteration: …